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C1 Maths help please!!

I don't understand how to do b) i)
Can anyone help?
thanks

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Reply 1
Avatar for sayema1
sayema1
14
umm there's nothing to see
Original post by mediaya
I don't understand how to do b) i)
Can anyone help?
thanks


No attachment :smile:
Original post by sayema1
umm there's nothing to see


Original post by _gcx
No attachment :smile:


one second, it's not uploading sorry
it probably involves a quadratic equation :teehee:
1490446241703.jpg

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Original post by _gcx
No attachment :smile:


Original post by sayema1
umm there's nothing to see


Original post by the bear
it probably involves a quadratic equation :teehee:


It's above ^
Sorry btw :lol:

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Reply 7
Avatar for sayema1
sayema1
14
that looks hard :s-smilie: which year is this from?
each term is nk.... so if there were 5 terms the 5th term would be 5k.... to get 5 you divide this by k....
Original post by sayema1
that looks hard :s-smilie: which year is this from?


Well it's alevel init :rofl:
May 2011 edexcel

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Original post by sayema1
that looks hard :s-smilie: which year is this from?


It is C1, so year 12.
Original post by mediaya


If we let the number of terms in the sequence be nn, then you would know that nk=100nk=100 (as the difference between each term is k, and we're looking at the nth term). How can you use this information to find the amount of terms in the sequence, considering that the question notes that kk is a factor of 100?
(edited 7 years ago)
Original post by the bear
each term is nk.... so if there were 5 terms the 5th term would be 5k.... to get 5 you divide this by k....


I dont understand. So there are 100 terms?
Dont get it

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Original post by mediaya
I dont understand. So there are 100 terms?
Dont get it

Posted from TSR Mobile


if there were 8 terms the last term would be 8k

if there were 37 terms the last term would be 37k...
http://www.examsolutions.net/exampapers/edexcel-c1-june-2011/ check this out hope this helps :smile:
Original post by mediaya
I dont understand. So there are 100 terms?
Dont get it

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We're looking at a sequence that increases by kk, and starts at T1=kT_1=k. So, we know that Tn=nkT_n=nk. We're looking for an expression for nn, such that nk=100nk=100. If I'm not being clear enough, maybe another member could fill me in.
IMG_20170325_130748.jpg
Hope this helps? I'm not too sure how clear it is though...
Original post by _gcx
If we let the number of terms in the sequence be nn, then you would know that nk=100nk=100 (as the difference between each term is k, and we're looking at the nth term). How can you use this information to find the amount of terms in the sequence, considering that the question notes that kk is a factor of 100?


1490447485934.jpg
Is this right?

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Original post by mediaya
1490447485934.jpg
Is this right?

Posted from TSR Mobile


Yes :smile:

The number of terms in the sequence is 100k\frac{100}{k}, given that kk is a factor of 100 (as stated in the question).
Original post by the bear
if there were 8 terms the last term would be 8k

if there were 37 terms the last term would be 37k...


Original post by sayema1


Original post by melissachung
IMG_20170325_130748.jpg
Hope this helps? I'm not too sure how clear it is though...


Original post by _gcx
Yes :smile:

The number of terms in the sequence is 100k\frac{100}{k}, given that kk is a factor of 100 (as stated in the question).


My god finally it took my an hour just to find this :mad2:
I'm not made for maths...no maths is not made for me :frown:
Only 2 months left i'm screwed...
Thank you everyone for saving me another hour :tongue:

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