Here's a thread for the best exam of them all!! Join fellow students preparing for the exam who like you are climbing slopes, raising pulleys, accelerating in lifts and playing on see-saws.
Graham is in the process of creating new Bronze Silver and Gold papers, removing the occasional repeated topics and using questions upto 2016. He has done new papers for C1 - C4 so far.
Hi!! I'm really worried for my Alevel Maths, and i was just wondering what we should be doing right now? Textbook questions? Solomon papers? or Practice papers? And how much should we be doing, I'm doing C1 C2 C3 C4 M1 S1 this year.
Hi!! I'm really worried for my Alevel Maths, and i was just wondering what we should be doing right now? Textbook questions? Solomon papers? or Practice papers? And how much should we be doing, I'm doing C1 C2 C3 C4 M1 S1 this year.
Thanks
Right now I'm doing past papers and occasionally Solomon papers but I think past papers are more useful, especially the more recent ones! Often the questions in the textbook aren't exam style so if you've finished "learning" the course the textbooks aren't that useful in my opinion.
In this question, how would you determine the direction of movement of each particle after the collision. Does particle B having a greater momentum mean that A moves in the opposite direction? but then how do you determines B's direction?
In this question, how would you determine the direction of movement of each particle after the collision. Does particle B having a greater momentum mean that A moves in the opposite direction? but then how do you determines B's direction?
You can assume the direction of the particles after the collision. Lets say you assume they both go to the right but then you calculate the velocity of A to be negative, then the maths shows that A was in fact reversed, since velocity is a vector and you assumed the direction to the right was positive.
You can assume the direction of the particles after the collision. Lets say you assume they both go to the right but then you calculate the velocity of A to be negative, then the maths shows that A was in fact reversed, since velocity is a vector and you assumed the direction to the right was positive.
Yes, I've tried the different ways, it all works, thanks.
Both sides of the string pull diagonally down on the pulley. Their horizontal components cancel out, with one going to the left and one to the right. So the resultant force on the pulley is their 2 vertical components, i.e. 2Tcos 60 vertically downwards.
Both sides of the string pull diagonally down on the pulley. Their horizontal components cancel out, with one going to the left and one to the right. So the resultant force on the pulley is their 2 vertical components, i.e. 2Tcos 60 vertically downwards.
Oh okay. It also says give the magnitude and direction, but T is in terms of mg, so what is the magnitude? And the direction?
my bad- I got confused with physics, best thing here is a force vector triangle, then cosine rule
Yeah I did that but didn't know how to get the magnitude. Do I use 1.2mg and square it while applying the cosine rule or does mg get cancelled somewhere along the way?
For resultant force questions e.g. resultant force on a pulley, there's always the option to draw a vector diagram i.e. a triangle of forces. If two forces acting are F1 and F2 then the resultant force is F1+F2. So you can draw the force vectors head to tail in a triangle:
It's not hard to show that this is an equilateral triangle so the magnitude of the resultant must be equal to T.
I always like this method but students are often not keen on it for some reason