I think the question is misprinted on the FP2 PAPER?

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FHL123
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Ihttp://crashmaths.com/wp-content/uploads/2016/09/FP2PPAMS.pdf

Q5 appears to calculate the region R as if it were bounded by the two curves. I think the mark scheme is wrong. I have attached my working below. If i am wrong could someone please point it out?

Thanks
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FHL123
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FHL123
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FHL123
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It can't be the semi circle- area of the triangle because the little segments bordering the triangle are still included?
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FHL123
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(Original post by FHL123)
It can't be the semi circle- area of the triangle because the little segments bordering the triangle are still included?
why has your working disappeared
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the bear
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you can do it without integration...

https://www.pdf-archive.com/2017/04/...20170402-0004/
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FHL123
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(Original post by the bear)
you can do it without integration...

https://www.pdf-archive.com/2017/04/...20170402-0004/
I can see that you've got the same answer as the mark scheme and I can see what you've done. But I still don't understand why my working was wrong ?
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the bear
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(Original post by FHL123)
why has your working disappeared
my first attempt went wrong :teehee:
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the bear
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(Original post by FHL123)
I can see that you've got the same answer as the mark scheme and I can see what you've done. But I still don't understand why my working was wrong ?
you have worked out the white part of the top circle... you need to subtract from the whole of the top circle to leave you with the shaded bits.
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FHL123
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(Original post by the bear)
you have worked out the white part of the top circle... you need to subtract from the whole of the top circle to leave you with the shaded bits.
I have done that? Ive worked out the area of the top circle to be 16pi and subtracted my integrated answer
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Jamvicious
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(Original post by FHL123)
I have done that? Ive worked out the area of the top circle to be 16pi and subtracted my integrated answer
Surely its only 4pi as the radius is 2
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FHL123
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(Original post by Jamvicious)
Surely its only 4pi as the radius is 2
I thought if I substitute pi/2 into r=4sinx it would give me the radius but as I write this I realise I have calculated the diameter 🙄😂 and that explains why my attempt was probably wrong
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FHL123
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(Original post by FHL123)
I thought if I substitute pi/2 into r=4sinx it would give me the radius but as I write this I realise I have calculated the diameter 🙄😂 and that explains why my attempt was probably wrong
This doesn't look right surely b should be 3? Have they factorised it wrong ?
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RDKGames
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(Original post by FHL123)

This doesn't look right surely b should be 3? Have they factorised it wrong ?
Yes they have. crashMATHS
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crashMATHS
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(Original post by RDKGames)
Yes they have. crashMATHS
Whoops! Will get that fixed, thanks!
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FHL123
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(Original post by crashMATHS)
Whoops! Will get that fixed, thanks!
Do you have the mark scheme for the corresponding FP2 Set C paper?
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crashMATHS
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(Original post by FHL123)
Do you have the mark scheme for the corresponding FP2 Set C paper?
That has not been made yet I'm afraid


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