I get ( see spoiler), but didn't use the fact that centre of C2 lies on circumference of C1 - can't see the relevance.
I should have said "find the numerical value of PQ without calculating the values a and b" or something like that.
Now I think about it, I should have gone with my original version - I toned it down a bit at the last minute as it seemed too tricky for most people to want to try. It's hard making up good problems.
I should have said "find the numerical value of PQ without calculating the values a and b" or something like that.
Now I think about it, I should have gone with my original version - I toned it down a bit at the last minute as it seemed too tricky for most people to want to try. It's hard making up good problems.
It tells you that the center of circle c2 lies on the circumference of c1, therefore this tells you that the radius of c2 is 1(try graph it on dermis) . So both of these circles have the same radius and they both cross over each like a ven diagram. So knowing this you can do abit of algebraic miniplaution to solve for the X and y coordinates of where they cross at the point. Pq
Yes, with the additional info added that I omitted at first.
It's probably easiest to do it by drawing a picture. Due to the symmetry in the coords of the points of intersection, we see that the centre of C2 lies on the line y=x. Now rotate the two circle by 45 degrees, so that the centre of C2 lies on the x-axis. It's now trivial to see that the points of intersection and the centres form equilateral triangles of side 1, from which the answer follows by Pythag. or simple trig.