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help me to solve this limit question.

lim (cos2x)^(1/x^2)=?
x--->0
Unparseable latex formula:

\equation{ u = \dfrac{1}{x^2}},[br][br]\equation{\cos{(\dfrac{2}{\sqrt{u}})}^u = (1-2\sin^2{(\dfrac{1}{\sqrt{u}}}))^u},[br] [br]In the limit: \equation{\sin{(\dfrac{1}{\sqrt{u}})}}[br]is close to:[br]\equation{ \dfrac{1}{\sqrt{u}}}}[br][br][br]so the limit is:[br]\equation{(1-\dfrac{2}{u})^{u} = e^{-2}}[br][br]



I know that's not the most rigorous of answers but I'll leave that to you
Unparseable latex formula:

[br]\equation{(1-\dfrac{2}{u})^{u} = e^{-2}}[br]

Original post by eugaurie
Unparseable latex formula:

[br]\equation{(1-\dfrac{2}{u})^{u} = e^{-2}}[br]


thank you
Original post by huvaxshatra
thank you


No problem! I don't know what level this question was set at but if you're studying at university it might help to include a line saying why you can replace one function by the other (possibly including the epsilon-delta definition of the limit of a function).
[QUOTE="eugaurie;70879180"]No problem! I don't know what this question was set at but if you're studying at it might help to include a line saying why you can replace one function by the other (possibly including the epsilon-delta definition of the limit of a function).[/QUOTE
you used Taylor series l think

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