shadyhades
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Hi, could someone please explain to me how to do part b in question 7 of this paper? I know we have to substitute the equation for a to find the value of T (which is 16.0645 N), but I'm at a loss after that.

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Here's a link for the mark scheme if you need: http://pmt.physicsandmathstutor.com/...%20Edexcel.pdf
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Kevin De Bruyne
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(Original post by shadyhades)
Hi, could someone please explain to me how to do part b in question 7 of this paper? I know we have to substitute the equation for a to find the value of T (which is 16.0645 N), but I'm at a loss after that.

Attachment 634770

Here's a link for the mark scheme if you need: http://pmt.physicsandmathstutor.com/...%20Edexcel.pdf
Please post Maths questions in the Maths forum.
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tiny hobbit
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(Original post by shadyhades)
Hi, could someone please explain to me how to do part b in question 7 of this paper? I know we have to substitute the equation for a to find the value of T (which is 16.0645 N), but I'm at a loss after that.

Attachment 634770

Here's a link for the mark scheme if you need: http://pmt.physicsandmathstutor.com/...%20Edexcel.pdf
I would use a more general method which will work whatever the angle is between the two pieces of the string.

The resultant will bisect the angle ACB, i.e will be at 45 degrees to each of them. The components of the tension for each bit of the string in this direction will be T cos 45, so the resultant will be 2T cos 45. The components at right angles to this will be in opposite directions and so will cancel out.

Knowing the direction of this resultant, you can work out the angle it makes with the vertical.
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runballadmix
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(Original post by tiny hobbit)
I would use a more general method which will work whatever the angle is between the two pieces of the string.

The resultant will bisect the angle ACB, i.e will be at 45 degrees to each of them. The components of the tension for each bit of the string in this direction will be T cos 45, so the resultant will be 2T cos 45. The components at right angles to this will be in opposite directions and so will cancel out.

Knowing the direction of this resultant, you can work out the angle it makes with the vertical.
how do you work out the angle it makes with the vertical?
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Prasiortle
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(Original post by runballadmix)
how do you work out the angle it makes with the vertical?
Just draw it and put in a suitable right-angled triangle with a horizontal and a vertical side. Then use simple trigonometry to find the angle between the diagonal and vertical side.
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