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Half equation for oxidation of chloride ions

What is it?
Original post by Federerr
What is it?


Oxidation is a loss of electrons. 2 Cl- ions will lose an electron each to form a Chlorine diatomic molecule. Don't forget to include the electrons in the equation!
Reply 2
Original post by K-Man_PhysCheM
Oxidation is a loss of electrons. 2 Cl- ions will lose an electron each to form a Chlorine diatomic molecule. Don't forget to include the electrons in the equation!


So is it:

2Cl- - 2e- ------> Cl2

or

2Cl- + 2e- -------> Cl2
Original post by Federerr
So is it:

2Cl- - 2e- ------> Cl2

or

2Cl- + 2e- -------> Cl2


Neither.

The second equation has no charge balancing.
The first equation isn't representative of how you write chemical equations. You don't minus anything in a chemical equation do you. In your head it should be 'This and this gives this', not 'this take away this gives this'. The way you write it isn't representative of the process at all either. It removes the implication that there are electrons that can be used by other things.

2Cl- ----> Cl2 + 2e-
Original post by Federerr
So is it:

2Cl- - 2e- ------> Cl2

or

2Cl- -------> Cl2 + 2e-

This is correct. The last equation that you that you entered is incorrect.
I think this one:

2Cl- -------> Cl2 + 2e-

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