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Help me solve this

9709/m/j/14/21
The reaction of ethane with bromine forms a mixture of products.

(iii) Give the equation for a termination step that could occur, producing a hydrocarbon.

(iv) Give the equation for one propagation step involved in the formation of dibromoethane
from bromoethane during this reaction.

I don't understand how to make the reaction proceed.
is this first step right?
C2H6+Br•--> C2H5Br• + HBr
Original post by anonymousvoice
9709/m/j/14/21
The reaction of ethane with bromine forms a mixture of products.

(iii) Give the equation for a termination step that could occur, producing a hydrocarbon.

(iv) Give the equation for one propagation step involved in the formation of dibromoethane
from bromoethane during this reaction.

I don't understand how to make the reaction proceed.
is this first step right?
C2H6+Br•--> C2H5Br• + HBr


Propagation means that you make another free radical, but your equation is not correct as you have magically produced two bromine atoms. It should be:
C2H6+Br•--> C2H5• + HBr
Original post by charco
Propagation means that you make another free radical, but your equation is not correct as you have magically produced two bromine atoms. It should be:
C2H6+Br•--> C2H5• + HBr


thank you lol, I get it now!

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