The Student Room Group
Reply 1
Not too sure about these as I'm pretty destroyed from hockey but....

1) N + H + H + H = 1.00g
N + H + H + H = 17 (RFM) N = 14 out of 17
Think about doing a percentage with the masses.

2) n = m/M then rearrange for mass of SO2.

Btw I'm assuming you are at least GCSE standard otherwise what I've said will make absolutely no sense at all :biggrin:
Reply 2
jason1988
Can anyone explain how i would solve this please :smile:?

Exercise 5

A sample of ammonia, NH3, weighs 1.00 g.

(a) What amount of ammonia is contained in this sample?

(b) What mass of sulphur dioxide, SO2, contains the same number of molecules as are in 1.00 g of ammonia?

Thanks! :wink:


To be honest, I have to begin by criticising the wording of the question. Part a) really donst make it clear that they want an answer in moles (I was initially inclinded to say that it contained 1.00g - well that is an amount isn't it!) You know this, because it's the only other way chemists have of expressing "amount" of a substance and also, part b) will require you to do this. So:

a) Moles = Mass/Mr

Mass=1.00g
Mr= 17

Therefore, 0.0588235
=0.0588moles (3SF)

b) Moles*Mr=Mass

Mr SO2= 64, So, 0.0588235...*64 = 3.76g (3SF)

Hope that was usefull :smile:
Reply 3
Henerz
To be honest, I have to begin by criticising the wording of the question. Part a) really donst make it clear that they want an answer in moles (I was initially inclinded to say that it contained 1.00g - well that is an amount isn't it!) You know this, because it's the only other way chemists have of expressing "amount" of a substance and also, part b) will require you to do this. So:

a) Moles = Mass/Mr

Mass=1.00g
Mr= 17

Therefore, 0.0588235
=0.0588moles (3SF)

b) Moles*Mr=Mass

Mr SO2= 64, So, 0.0588235...*64 = 3.76g (3SF)

Hope that was usefull :smile:


I havent checked these, but please dont post full solutions in future - they need to understand and work through it themselves.