A student adds 50 cm3 of 0.25 moldm^-3 butanoic axid to 50cm of 0.05 moldm-3 NaOH.... can someone explain to me why the conc of the acid is 0.1? I'm getting 0.125
A student adds 50 cm3 of 0.25 moldm^-3 butanoic axid to 50cm of 0.05 moldm-3 NaOH.... can someone explain to me why the conc of the acid is 0.1? I'm getting 0.125
The question is, how did you get 0.125. Equal volumes of both solutions, so 0.25 - 0.05 = 0.2, but the volume doubles, so 0.2 / 2 = 0.1
The question is, how did you get 0.125. Equal volumes of both solutions, so 0.25 - 0.05 = 0.2, but the volume doubles, so 0.2 / 2 = 0.1
and why with equal volumes can you just minibus the conc of Naoh off the conc of the acid.. I understand that when you double the volume to concentration will have
and why with equal volumes can you just minibus the conc of Naoh off the conc of the acid.. I understand that when you double the volume to concentration will have
Do you realise there's a nuetralisation reaction happening, water is created