Gmart
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Given that: $f(x) = 8x^3+4x-3$
find the remainder if it exists, when $\frac{1}{f(x)}$ is divided by $x+1$

I cannot find a method to do this question, it should be remainder theorem, but do I multiply them and then find the roots by working thru the factors?
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Gmart
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PS, my first Latex post so be kind
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atsruser
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(Original post by Gmart)
PS, my first Latex post so be kind
+ve rep for the latex. But is that the real question? You want to divide 1/f(x)?
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Gmart
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(Original post by atsruser)
+ve rep for the latex. But is that the real question? You want to divide 1/f(x)?
Maybe my hap-handed latex is distracting. Here is the original question from the book:

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and the answer is that it does not exist, and yet I don't know why?
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Plücker
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(Original post by Gmart)
Maybe my hap-handed latex is distracting. Here is the original question from the book:

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and the answer is that it does not exist, and yet I don't know why?
\frac{1}{f(x)} is not a polynomial.
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username1732491
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(Original post by Gmart)
Given that: $f(x) = 8x^3+4x-3$
find the remainder if it exists, when $\frac{1}{f(x)}$ is divided by $x+1$

I cannot find a method to do this question, it should be remainder theorem, but do I multiply them and then find the roots by working thru the factors?
My only guess would be to use the Taylor theorem to expand $\frac{1}{f(x)}$, then try and see if it's obvious from the first few terms. Not sure how else to do it though
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