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A2 chem help!

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    Hi does anyone know how to do this question? Name:  ImageUploadedByStudent Room1492800472.583956.jpg
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    The question says "1g of chlorine radicals" the 1 was cut off on the photo.
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    (Original post by medicapplicant)
    Hi does anyone know how to do this question? Name:  ImageUploadedByStudent Room1492800472.583956.jpg
Views: 14
Size:  94.3 KB

    The question says "1g of chlorine radicals" the 1 was cut off on the photo.

    EDIT: can someone please work it out so I can compare my answer to it thanks.
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    Isnt that from the mock practise papers?
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    7.41 x 10^-6

    Not too confident with answer btw
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    (Original post by DisturbedCustard)
    Isnt that from the mock practise papers?
    yeah we did it in class yesterday
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    (Original post by medicapplicant)
    yeah we did it in class yesterday
    We did it on Tuesday. I left that question out as it baffled me too! I just worked out moles and number of molecules in 1g and left it. Might get one method Mark.
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    i got 9.98x10^4 dont know if its right
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    i did:

    Cl (mol): O3(mol)
    0.0282:2812.5
    1:99843.75

    then
    n of cl radicals x avagardos= 1(because the question says 1 chlorine radical)
    worked out n to be= 1/(6.02 x 10^23)
    then using the mol ratio above of chlorine to ozone woeked out ozone mol and times that by avagardos costant to get 9.98x10^4
    did someone else do something similar
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    This is what i did, but could be completely wrong.

    1g Cl reacts with 135x10^3g O3

    1/35.5 Moles of Cl reacts with 135x10^3/48 Moles of O3

    Multiply both sides by Avogradros to get number of particles of each, then divide both by the number of Cl particles = 9.98x10^3 O3 molecules

    EDIT: Previously had O2, not O3
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    (Original post by HopelessMedic)
    This is what i did, but could be completely wrong.

    1g Cl - 135x10^3g O2

    1/35.5 Moles of Cl reacts with 135x10^3/32 Moles of O2

    Multiply both sides by Avogradros to get number of particles of each, then divide both by the number of Cl particles = 149.77x10^3 O2 Molecules
    i see what you did, i did that at first too but the question says 1 chlorine radical, so the mol of chlorine wouldnt be 1/35.5 but rather n=1/6.02 x10^23 but then again im not certain thats right
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    (Original post by medicapplicant)
    i see what you did, i did that at first too but the question says 1 chlorine radical, so the mol of chlorine wouldnt be 1/35.5 but rather n=1/6.02 x10^23 but then again im not certain thats right
    The Chlorine radical still has the same mass as a Chlorine atom though, the only difference is an unpaired electron which has no mass?

    EDIT: I made a mistake before, we have the same answer now.
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    (Original post by HopelessMedic)
    The Chlorine radical still has the same mass as a Chlorine atom though, the only difference is an unpaired electron which has no mass?

    EDIT: I made a mistake before, we have the same answer now.
    oh ok.
 
 
 
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