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# A2 chem help! watch

1. Hi does anyone know how to do this question?

The question says "1g of chlorine radicals" the 1 was cut off on the photo.
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2. (Original post by medicapplicant)
Hi does anyone know how to do this question?

The question says "1g of chlorine radicals" the 1 was cut off on the photo.

EDIT: can someone please work it out so I can compare my answer to it thanks.
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3. Isnt that from the mock practise papers?
4. 7.41 x 10^-6

Not too confident with answer btw
5. (Original post by DisturbedCustard)
Isnt that from the mock practise papers?
yeah we did it in class yesterday
6. (Original post by medicapplicant)
yeah we did it in class yesterday
We did it on Tuesday. I left that question out as it baffled me too! I just worked out moles and number of molecules in 1g and left it. Might get one method Mark.
7. i got 9.98x10^4 dont know if its right
8. i did:

Cl (mol): O3(mol)
0.0282:2812.5
1:99843.75

then
n of cl radicals x avagardos= 1(because the question says 1 chlorine radical)
worked out n to be= 1/(6.02 x 10^23)
then using the mol ratio above of chlorine to ozone woeked out ozone mol and times that by avagardos costant to get 9.98x10^4
did someone else do something similar
9. This is what i did, but could be completely wrong.

1g Cl reacts with 135x10^3g O3

1/35.5 Moles of Cl reacts with 135x10^3/48 Moles of O3

Multiply both sides by Avogradros to get number of particles of each, then divide both by the number of Cl particles = 9.98x10^3 O3 molecules

EDIT: Previously had O2, not O3
10. (Original post by HopelessMedic)
This is what i did, but could be completely wrong.

1g Cl - 135x10^3g O2

1/35.5 Moles of Cl reacts with 135x10^3/32 Moles of O2

Multiply both sides by Avogradros to get number of particles of each, then divide both by the number of Cl particles = 149.77x10^3 O2 Molecules
i see what you did, i did that at first too but the question says 1 chlorine radical, so the mol of chlorine wouldnt be 1/35.5 but rather n=1/6.02 x10^23 but then again im not certain thats right
11. (Original post by medicapplicant)
i see what you did, i did that at first too but the question says 1 chlorine radical, so the mol of chlorine wouldnt be 1/35.5 but rather n=1/6.02 x10^23 but then again im not certain thats right
The Chlorine radical still has the same mass as a Chlorine atom though, the only difference is an unpaired electron which has no mass?

EDIT: I made a mistake before, we have the same answer now.
12. (Original post by HopelessMedic)
The Chlorine radical still has the same mass as a Chlorine atom though, the only difference is an unpaired electron which has no mass?

EDIT: I made a mistake before, we have the same answer now.
oh ok.

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