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Edexcel IAL chemistry unit 6B 16/5/2017 exam thread

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Reply 40
Jan 2017 unit 6 is messed up! I dont know what to expect this time!
Reply 41
Original post by pondsteps
wtf is this june 2016 paper??!!! did anyone attempt it ???? i was solving all the papers and everything was going fine now i solved that paper and i feel so depressed and unready for the exam!!! ughhhhhh i neeed help with it


exactlyidk what to do either.
after solving jan17 and june 16 im just so depressed idk what to do :frown:
ImageUploadedByStudent Room1494825886.572777.jpg

Could somebody please explain the answer of b to me? 😢


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Original post by shady zax
ImageUploadedByStudent Room1494825886.572777.jpg

Could somebody please explain the answer of b to me? 😢


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is this unit 6 chem or unit 4:K: which year is it??
Original post by shady zax
ImageUploadedByStudent Room1494825886.572777.jpg

Could somebody please explain the answer of b to me? 😢


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isnt the answer cos reaction 1 is the rate determining step
Original post by pondsteps
isnt the answer cos reaction 1 is the rate determining step


If u combine the last two equations u get the equation in 1..so..?


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Probably so that the iodate and hydrogensulfate have a chance of participating in reactions 2 and 3
If reaction 1 was too fast then they would be completely used up😫😫😫 I hope
Original post by shady zax
ImageUploadedByStudent Room1494825886.572777.jpg

Could somebody please explain the answer of b to me? 😢


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I think it's because both IO3- and HSO3- should be in the rate determining step and reaction 1 is the only reaction where they are both present as reactants.

I'm not completely sure though so if you find out the answer please do let me know.
Reply 48
Part ( c)

why isn't the color change from colorless to pink
since the Kmno4 i added to the Fe solution
Reply 49
This too??? why shouldn't it be colorless to pink
since KMNo4 is added to Glucosee
Original post by hiyoriiki183
Probably so that the iodate and hydrogensulfate have a chance of participating in reactions 2 and 3
If reaction 1 was too fast then they would be completely used up😫😫😫 I hope


The answer is to avoid the formation of the black colour too soon..wats that mean?


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Original post by dr-jekyll
I think it's because both IO3- and HSO3- should be in the rate determining step and reaction 1 is the only reaction where they are both present as reactants.

I'm not completely sure though so if you find out the answer please do let me know.


Huh? 😢


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Original post by cool99w
This too??? why shouldn't it be colorless to pink
since KMNo4 is added to Glucosee


It should be pink to colourless ..i think.. Purple manganate is reduced to mn2+ by the glucose... As this only gradually happens purple solution gradually gets paler until at the end point the last of the mno4- is converted to colourless mn2+


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Does anybody know the identity of the black ppt from an unsuccessful positive silver mirror test?


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Where can I find the jan 2017 paper?

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Reply 55
Original post by shady zax
It should be pink to colourless ..i think.. Purple manganate is reduced to mn2+ by the glucose... As this only gradually happens purple solution gradually gets paler until at the end point the last of the mno4- is converted to colourless mn2+


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But you are adding the mno4 to the flask which contains glucose
Original post by Willandy123
Where can I find the jan 2017 paper?

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Google: jan 17 edexcel ial bilal ahmed


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(edited 6 years ago)
I find those organic questions hard
guys should i revise the topics in details like rates entropy and that sorta stuff
Original post by pondsteps
guys should i revise the topics in details like rates entropy and that sorta stuff


I think just going through them once would be fine

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