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How do you do this question? - OCR Chem A

Hi I was struggling with this question and was wondering if anyone could help -
This question looks at groups in the periodic table. (a) Calcium and strontium are Group 2 metals. They both react with water. A chemist reacts 0.200 g of strontium with 250 cm3 water, leaving a colourless solution containing strontium ions. The volume remains at 250 cm3.
Calculate the concentration, in mol dm–3, of strontium ions in the resulting solution.
1) Construct an equation for the reaction with water
2) Work out how many moles of the strontium ions you will have afterwards, assuming the strontium product dissolves
3) Use this to calculate the concentration
Reply 2
Equation is: Sr(s) + 2H2O(g) Sr(OH)2(aq) + H2(g). We can work out the number of moles by using mol=mass/Mr. Mr of Strontium = 87.6. Therefore, 0.200/87.6 = 0.00228 (3.s.f). Therefore, there are 0.00228 mol of Sr(OH)2, as the mole ratio is 1:1 in the equation.

To find the conc. of the Sr(OH)2, we can use mol=conc. x vol., rearranged to give conc. = mol./vol.. As the question has told you that you have 250cm3 of solution at the end, we can do conc. = 0.00228/0.25 = 0.00913 mol dm-3.

Hope this helps! (I think I've done it correctly...no guarantees though!)
Reply 3
Original post by gd99
Equation is: Sr(s) + 2H2O(g) Sr(OH)2(aq) + H2(g). We can work out the number of moles by using mol=mass/Mr. Mr of Strontium = 87.6. Therefore, 0.200/87.6 = 0.00228 (3.s.f). Therefore, there are 0.00228 mol of Sr(OH)2, as the mole ratio is 1:1 in the equation.

To find the conc. of the Sr(OH)2, we can use mol=conc. x vol., rearranged to give conc. = mol./vol.. As the question has told you that you have 250cm3 of solution at the end, we can do conc. = 0.00228/0.25 = 0.00913 mol dm-3.

Hope this helps! (I think I've done it correctly...no guarantees though!)


Great thanks!
Reply 4
Original post by Alfieee
Great thanks!


You're welcome.
Original post by gd99
Equation is: Sr(s) + 2H2O(g) Sr(OH)2(aq) + H2(g). We can work out the number of moles by using mol=mass/Mr. Mr of Strontium = 87.6. Therefore, 0.200/87.6 = 0.00228 (3.s.f). Therefore, there are 0.00228 mol of Sr(OH)2, as the mole ratio is 1:1 in the equation.

To find the conc. of the Sr(OH)2, we can use mol=conc. x vol., rearranged to give conc. = mol./vol.. As the question has told you that you have 250cm3 of solution at the end, we can do conc. = 0.00228/0.25 = 0.00913 mol dm-3.

Hope this helps! (I think I've done it correctly...no guarantees though!)

Thanks I was looking all over for this answer too!

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