Daps1999
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Nitric acid is produced industrially from ammonia, air and water using the following sequence of reactions:

(1) 4NH3 (g) + 5O2(g) → 4NO(g) + 6H2O(g) ∆H = –909 kJ mol−1
(2) 2NO(g) + O2(g) → 2NO2(g) ∆H = –115 kJ mol−1
(3) 3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g) ∆H = –117 kJ mol−1
Which is the enthalpy change (in kJ mol−1) for the following reaction?
4NH3(g) + 7O2(g) → 4NO2(g) + 6H2O(g)
A −679
B −794
C −1024
D −1139

could help me solve me it pls and explain at the same time i get some of
it but yhh help
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username3112014
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l am trying to solve it
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Daps1999
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(Original post by huvaxshatra)
l am trying to solve it
The answer is D by the way just dont know how they got the answer D
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username3112014
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(1) 4NH3 (g) + 5O2(g) → 4NO(g) + 6H2O(g) ∆H = –909 kJ mol−1
(2) 4NO(g) + 4O2(g) → 4NO2(g) ∆H = –230 kJ mol−1
-230-909=-1139
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Daps1999
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(Original post by huvaxshatra)
(1) 4NH3 (g) + 5O2(g) → 4NO(g) + 6H2O(g) ∆H = –909 kJ mol−1
(2) 4NO(g) + 4O2(g) → 4NO2(g) ∆H = –230 kJ mol−1
-230-909=-1139
explain pls
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username3112014
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(Original post by Daps1999)
explain pls
sorry my English is not so good to explain well.other members will explain you.
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