# Serial Dilutions - AS Biology

Announcements
#1
Hi, I was wondering whether there was a formula to calculate the end concentrations of serial dilutions and how I would apply this to questions.

E.g. 1cm^3 of 2M hydrochloric acid was added to 9cm^3 of distilled water. The mixture was inverted, then 1cm^3 of the mixture was added to a further 9cm^3 of distilled water. What was the final concentration?

0
5 years ago
#2
C1*v1=c2*v2
0
5 years ago
#3
0.02moldm^-3
0
#4
(Original post by Jsisnxjdnd)
C1*v1=c2*v2
Ah thank you, but how would you apply this to this question in particular?
0
#5
(Original post by aytuiq)
0.02moldm^-3
Thank you
1
5 years ago
#6
No problem !

Good luck with your exam !
0
5 years ago
#7

1cm^3 2M HCl added to 9cm^3 of water means there is a final volume of 10cm^3 with a dilution of 1:10 and 2M/10=0.2M,
This is repeated with 9cm^3 again, so divide concentration by 10 again.

Further help:

https://socratic.org/questions/how-d...n-calculations
1
#8
(Original post by aytuiq)

1cm^3 2M HCl added to 9cm^3 of water means there is a final volume of 10cm^3 with a dilution of 1:10 and 2M/10=0.2M,
This is repeated with 9cm^3 again, so divide concentration by 10 again.

Further help:

https://socratic.org/questions/how-d...n-calculations
Thank you so much! You too
0
1 year ago
#9
(Original post by anona1255)
Ah thank you, but how would you apply this to this question in particular?
It applies to all dilution calculations. You want to keep the moles before the same as moles after (moles being CV)
0
X

new posts
Back
to top
Latest

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### Poll

Join the discussion

#### Y13s: How will you be receiving your A-level results?

In person (69)
69.7%
In the post (3)
3.03%
Text (13)
13.13%
Something else (tell us in the thread) (14)
14.14%

View All
Latest

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?