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Trignometric identities question help
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BabzY
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For solutions in the range -180 < theta < 180
The answer is 30 and 150 degrees but i would like to see the method for this question, any help is appreciated
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RDKGames
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(Original post by BabzY)
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For solutions in the range -180 < theta < 180
The answer is 30 and 150 degrees but i would like to see the method for this question, any help is appreciated
For solutions in the range -180 < theta < 180
The answer is 30 and 150 degrees but i would like to see the method for this question, any help is appreciated
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the bear
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BabzY
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#4
1 + tan^2 theta = sec^2 theta , using that i get a quadratic equation by subbing sec^2 theta -1 for tan^2 theta however when i work it out my answer doesn't match the one in the book
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RDKGames
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(Original post by BabzY)
1 + tan^2 theta = sec^2 theta , using that i get a quadratic equation by subbing sec^2 theta -1 for tan^2 theta however when i work it out my answer doesn't match the one in the book
1 + tan^2 theta = sec^2 theta , using that i get a quadratic equation by subbing sec^2 theta -1 for tan^2 theta however when i work it out my answer doesn't match the one in the book
??
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the bear
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BabzY
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#8
hahaha, thanks guys. Was using the correct method but forgot all about the calculator settings
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