E = mc^2 help
Need help with this question
I worked out the energy in one year
(3.8 x 10^26) * ( 3.2 x 10^2) = 1.2 x 10^34J
Mass = E/C^2
Which gave me 1.33 x 10^17 per year, so thats how much it emits per year
So 2 x 10^30 / (1.33 x 10^17) = 1.5 x 10 ^13.
However I'm out by a factor of 10^6. As the answer is 1.5 x 10^7, what have I done wrong thanks.
I worked out the energy in one year
(3.8 x 10^26) * ( 3.2 x 10^2) = 1.2 x 10^34J
Mass = E/C^2
Which gave me 1.33 x 10^17 per year, so thats how much it emits per year
So 2 x 10^30 / (1.33 x 10^17) = 1.5 x 10 ^13.
However I'm out by a factor of 10^6. As the answer is 1.5 x 10^7, what have I done wrong thanks.
Original post by Super199
Need help with this question
I worked out the energy in one year
(3.8 x 10^26) * ( 3.2 x 10^2) = 1.2 x 10^34J
Mass = E/C^2
Which gave me 1.33 x 10^17 per year, so thats how much it emits per year
So 2 x 10^30 / (1.33 x 10^17) = 1.5 x 10 ^13.
However I'm out by a factor of 10^6. As the answer is 1.5 x 10^7, what have I done wrong thanks.
I worked out the energy in one year
(3.8 x 10^26) * ( 3.2 x 10^2) = 1.2 x 10^34J
Mass = E/C^2
Which gave me 1.33 x 10^17 per year, so thats how much it emits per year
So 2 x 10^30 / (1.33 x 10^17) = 1.5 x 10 ^13.
However I'm out by a factor of 10^6. As the answer is 1.5 x 10^7, what have I done wrong thanks.
You are meant to divide a millionth of the mass by the rate (hence why you are out by x10^6). You calculated how long it would take to lose its entire amount of mass.
Original post by Vikingninja
You are meant to divide a millionth of the mass by the rate (hence why you are out by x10^6). You calculated how long it would take to lose its entire amount of mass.
ooo thanks. I didn't read the question properly thanks.
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