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# Mr M's OCR (not OCR MEI) Further Pure 1 Answers May 2017 watch

1. (Original post by eltree)
if you forgot to rationalise the denominator would you still get full marks?
Yes
2. also is there anyway to see what the diagram was mean to be for question 6i?
3. (Original post by Mr M)
Mr M's OCR (not OCR MEI) Further Pure 1 answers May 2017

1. (5 marks)

2. (5 marks)

3. (i) (2 marks)

(ii) (3 marks)

4. Proof (5 marks)

5. (i) Shear with x axis invariant taking (0, 1) to (5, 1) (3 marks)

(ii) (2 marks)

(iii) (2 marks)

(iv) 4 (2 marks)

6. (i) Sketch (3 marks)

(ii) and (5 marks)

(iii) Perpendicular bisector of line segment joining and (2 marks)

7 (i) Show (1 mark)

(ii) 0.629 (5 marks)

(iii) (1 mark)

8. a = -24, b = 45, c = -52 (7 marks)

9 (i) a = 2 (5 marks)

(ii) Any value other than a = 2 (1 mark)

(iii) p = -1 (3 marks)

10 (i) Show (4 marks)

(ii) (6 marks)

Thanks to Mr K and Mr H for their work on this.
Mr M,
1)For 6iii I described the line using the angle above the x-axis (along with some other details) but didn't mention that it was the perpendicular bisector. Would I lose any marks?
2)For showing z1-z2 on the Argand diagram, how much labelling do you need? I drew it in the right place (I think), and drew it as part of a parallelogram with the origin and z1 and z2.
3) For 10ii, I left the whole thing under the square root, +-√(a^2/3). Is there any penalty for this?
Thanks!
4. (Original post by eltree)
also is there anyway to see what the diagram was mean to be for question 6i?
Mr H's artwork.
Attached Images

5. (Original post by ts241)
Mr M,
1)For 6iii I described the line using the angle above the x-axis (along with some other details) but didn't mention that it was the perpendicular bisector. Would I lose any marks?
2)For showing z1-z2 on the Argand diagram, how much labelling do you need? I drew it in the right place (I think), and drew it as part of a parallelogram with the origin and z1 and z2.
3) For 10ii, I left the whole thing under the square root, +-√(a^2/3). Is there any penalty for this?
Thanks!
1) Not enough for full marks

2) That sounds good

3) Probably still ok
6. (Original post by Mr M)
Mr H's artwork.
Hi Mr M,On 6i) I had the points in the right place and shower working to get the exact values but drew them as points instead of lines. How many marks will I lose?
7. Minor point I know, but is - √2i fine rather than -i√2?
8. (Original post by Mr M)
Mr M's OCR (not OCR MEI) Further Pure 1 answers May 2017

1. (5 marks)

2. (5 marks)

3. (i) (2 marks)

(ii) (3 marks)

4. Proof (5 marks)

5. (i) Shear with x axis invariant taking (0, 1) to (5, 1) (3 marks)

(ii) (2 marks)

(iii) (2 marks)

(iv) 4 (2 marks)

6. (i) Sketch (3 marks)

(ii) and (5 marks)

(iii) Perpendicular bisector of line segment joining and (2 marks)

7 (i) Show (1 mark)

(ii) 0.629 (5 marks)

(iii) (1 mark)

8. a = -24, b = 45, c = -52 (7 marks)

9 (i) a = 2 (5 marks)

(ii) Any value other than a = 2 (1 mark)

(iii) p = -1 (3 marks)

10 (i) Show (4 marks)

(ii) (6 marks)

Thanks to Mr K and Mr H for their work on this.
Hi,
On 5i could you say "shear with x axis invariant by shear factor 4"?
9. (Original post by Hyih)
Minor point I know, but is - √2i fine rather than -i√2?
Depends if the i is inside the root or not.
Hi,
On 5i could you say "shear with x axis invariant by shear factor 4"?
Would it not be shear factor 5?
11. (Original post by britishtf2)
Depends if the i is inside the root or not.
Outside
Hi Mr M,On 6i) I had the points in the right place and shower working to get the exact values but drew them as points instead of lines. How many marks will I lose?
Points should be fine.
13. (Original post by Hyih)
Outside
Multiplication of complex numbers is commutative, so it's fine.
14. (Original post by Hyih)
Minor point I know, but is - √2i fine rather than -i√2?
Yes so long as your square root symbol clearly doesn't extend above the i.
15. (Original post by britishtf2)
Would it not be shear factor 5?
Yeah sorry, I forgot what the q was. The matrix was of the form 1k01 and I said shear factor k. I've forgotten what number k was
Yeah sorry, I forgot what the q was. The matrix was of the form 1k01 and I said shear factor k. I've forgotten what number k was
As far as I understand, it is correct, if shear factor 5. Please don't quote me on it though xd
Hi,
On 5i could you say "shear with x axis invariant by shear factor 4"?
If you put shear factor 5 then yes.
18. (Original post by britishtf2)
As far as I understand, it is correct, if shear factor 5. Please don't quote me on it though xd
Yes that's ok.
19. (Original post by Mr M)
Yes that's ok.
Good to know I understand maths... outside of exams -.-
20. Has anyone done a walkthrough for question 10 ii).?

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