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Edexcel Maths FP1 UNOFFICIAL Mark Scheme 19th May 2017

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    donnaseemchandra
    How are you feeling?
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    For the record, I noticed on an IAL paper that if you don't use the geometric progression formula from C2, you immediately lose 2 marks, they didn't accept simply plugging in numbers from 1 to 12
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    What were the 2 starting matrices in question 2 and how much was that question worth per part?
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    Also for the matrix question where it was AB +2A= kI, me and my friends got p=3/2, k=15/2
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    (Original post by Redcoats)
    Random answers:

    Sign change (-0.8888888 to 1.4149....)
    alpha = 6.45
    lambda = +- 4sqrt(5)
    a = 9/2 or -27/2
    Area (FXD) 15/16 a^2
    D: (-a , -3/2 a)
    Induction at the end (use assumption)
    k = 2/9 for sum
    other root: -3-2i
    a = 2
    b = -11 (or something like that)
    y=x/2 xy=16 (4sqrt(2), 2sqrt(2)) and (-4sqrt(2),-2sqrt(2))
    p = 20 somewhere

    Anyone else remember?
    agree with all ) hope we're on for 75/75
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    (Original post by arniethepie)
    For the record, I noticed on an IAL paper that if you don't use the geometric progression formula from C2, you immediately lose 2 marks, they didn't accept simply plugging in numbers from 1 to 12
    link?
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    anyone else get a=5 , or a=-13
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    Redcoats, I have done questions separately if you want to order the OP.

    I should be able to access the paper tomorrow, I've seen all the mark schemes so should be able to guess how the marks are structured once I've had a good luck.
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    (Original post by k.russell)
    -27/2 because -27/2 x 2 + 9 = -18. The scale factor is absolute value of det m, so you need to find a such that det m = +/-18
    ahh do you think you would get 3/5 for getting one solution?
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    These are my answers, looking for mild confirmation, here also are the marks:

    1) This was a newton r f(x)=\frac{1}{3}x^2+\frac{4}{x^2  }-2x-1

    a) Prove root [6,7] Change of sign (2 marks)
    b) Find first newton approx starting at 6 to 2dp , 6.45 (5 marks)

    2) some matrix question:
    A=\begin{bmatrix} 2 & -1 \\ 4 & 3 \end{bmatrix}
    (a) A^{-1} = \frac{1}{10}\begin{bmatrix} 3 & 1 \\ -4 & 2 \end{bmatrix} (2 marks)

    P=\begin{bmatrix} 3 & 6 \\ 11 & -8 \end{bmatrix}

    (b) Given AB=P find B B = \begin{bmatrix} 2 & 1 \\ 1 & -4 \end{bmatrix} (3 marks)

    3)
    x=4t , x=\frac{4}{t}
    a) Find a line perpendicular to line between points t=\frac{1}{4} and t=2 that goes through origin. Ans: y=\frac{1}{2}x (3 marks)
    b) cart equation y=\frac{16}{x}

    c) Points of intersection (4\sqrt{2},2\sqrt{2}) and (-4\sqrt{2},-2\sqrt{2}) (3 marks)

    4) Complex Numbers, horra.
    i) w=\frac{p-4i}{2-3i}
    a) a+bi form : \frac{2p+12}{13}+\frac{3p-8}{13}i (3 marks)
    arg(w) = \frac{\pi}{4}
    b) p=20 (2 marks)
    ii) z=(1-\lambda i)(4+3i) , \mid z \mid = 45

    \lambda = \pm 4\sqrt{5} (2 marks)

    5) i)
    A= \begin{bmatrix} p & 2 \\ 3 & p \end{bmatrix} , B= \begin{bmatrix} -5 & 4 \\ 6 & -5 \end{bmatrix}
    (a) Find AB (2)
    AB + 2A = kI
    find k and p
    (b) p=\frac{3}{2} , k = \frac{15}{2}

    ii) I forget what the question was but a=\frac{9}{2} and \frac{-27}{2}(5 marks)

    6 (a) -2-3i (1)
    (x-4)(x+2-3i)(x+2+3i)
    (b) a=2 b=-11 (5 marks)
    7 (a) (4 marks)
    (b) (4 marks)
    (c)  \frac{15}{16}a^2 (2 marks)

    8) Proof involving sums:
    (a) (5 marks)
    (b) \frac{2}{9} (4 marks)

    9) two proofs questions, each worth 6 marks


    Thanks To:
    - @k.russell for 5 ii second answer
    - @DystopiaisReal for 5 a, I put down the wrong sign
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    a=4.5,-13.5
    k=2/9
    p=1.5
    k=7.5
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    (Original post by Nik298)
    ahh do you think you would get 3/5 for getting one solution?
    tbh I am not sure, I reckon that sounds fair though
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    (Original post by X_IDE_sidf)
    These are my answers, looking for mild confirmation, here also are the marks:

    1) This was a newton r f(x)=\frac{1}{3}x^2+\frac{4}{x^2  }-2x-1

    a) Prove root [6,7] Change of sign (2 marks)
    b) Find first newton approx starting at 6 to 2dp , 6.45 (5 marks)

    2) some matrix question:
    A=\begin{bmatrix} 2 & -1 \\ 4 & 3 \end{bmatrix}
    (a) A^-1 = \frac{1}{10}\begin{bmatrix} 3 & 1 \\ -4 & 2 \end{bmatrix} (2 marks)

    P=\begin{bmatrix} 3 & 6 \\ 11 & -8 \end{bmatrix}

    (b) Given AB=P find B B = \begin{bmatrix} 2 & 1 \\ 1 & -4 \end{bmatrix} (3 marks)

    3)
    x=4t , x=\frac{4}{t}
    a) Find a line perpendicular to line between points t=\frac{1}{4} and t=2 that goes through origin. Ans: y=\frac{1}{2}x (3 marks)
    b) cart equation y=\frac{16}{x}

    c) Points of intersection (4\sqrt{2},2\sqrt{2}) and (-4\sqrt{2},-2\sqrt{2}) (3 marks)

    4) Complex Numbers, horra.
    i) w=\frac{p-4i}{2-3i}
    a) a+bi form : \frac{2p+12}{13}+\frac{3p+8}{13}  i (3 marks)
    arg(w) = \frac{\pi}{4}
    b) p=20 (2 marks)
    ii) z=(1-\lambda i)(4+3i) , \mid z \mid = 45

    \lambda = \pm 4\sqrt{5} (2 marks)

    what question was the p=20 one?
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    I ****ed up all the induction, could i still get some marks?
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    I had a wicked nosebleed round solving question 10 and it broke my concentration
    Sooooo disappointing...
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    Do you guys remember the question about summations that led to k = 2/9.
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    Question 9i solution/answer.
    Name:  IMG_3030.jpg
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    Can you please do it for the k series question?
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    Question 9ii solution/answer.
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    (Original post by 04MR17)
    Question 2: Matrices
    a.) 1 .(3. 1)
    ....10 (-4 2) [2]
    b.) (2. 1)
    .....(1 -4) [3]
    The determinant was 10??? Oh ffs
 
 
 
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