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# Edexcel Maths FP1 UNOFFICIAL Mark Scheme 19th May 2017 watch

1. (Original post by KingsAlpaca)
1. ST 6.45
2. (3/10, 1/10
-2/5, 1/5)
(2,1
1,-4)
3. y=x/2 xy=16 (4sqrt(2), 2sqrt(2)) and (-4sqrt(2),-2sqrt(2))
4. (2p+12)/13 + (3p-8)i/13 p=20 lambda=+-4sqrt(5)
5. (12-5p, 4p-10
6p-15, 12-5p)
p=3/2 k=15/2 a=9/2 or -27/2
6. -3-2i a=2 b=-11
7. ST (-a, -3a/2) s=15a^2/16
8. ST k=2/9
9. ST ST
If I did not get number 7 and number 6 totally right, would it be A still? I am sure I got the other right.
2. I got the same answer but youre supposed to calculate q and simplify the answers with it which i didnt.
How many marks do u think i will lose?
(I left the y coordinate and area in terms of a and q)

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3. how many marks for the -27/2 one? i missed out this!
4. for the last induction question i changed f(k+1) into the same format as f(k) and then when i added 11f(k) it was divisible by 19. does this sound vaguely right to anyone?? had no idea what i was doing lol
5. (Original post by X_IDE_sidf)
How did you solve this one, tbh I just added it 12 times
So you know the summation formula which was n/2(n+3)(2n+5) if i recall correctly, put 12 in and you got 2610.
so 2610 + k(2^(r-1)) = 3520
k(2^(r-1)) = 910
now as r is increasing you need to do K(2^0 + 2^1 + 2^2... 2^11) = 910
it came to 910/4095 = 2/9
Am i the only one who forgot the sum for 2 to the power of r-1 from c2 so manually wrote out all 12 terms such mathematical elegance
I love that xD
Did the same thing.
Worried I may loose marks on it?( Method marks)
7. (Original post by 20XX Fox)
Misread the equation for newton raphson to have be +4/x^2 rather than -. How many marks will I lose
Bump
8. (Original post by erawein)
So you know the summation formula which was n/2(n+3)(2n+5) if i recall correctly, put 12 in and you got 2610.
so 2610 + k(2^(r-1)) = 3520
k(2^(r-1)) = 910
now as r is increasing you need to do K(2^0 + 2^1 + 2^2... 2^11) = 910
it came to 910/4095 = 2/9
This is how I did it, but the comment was made that the geometric series formula in C2 would have been more elegant ( https://www.varsitytutors.com/hotmat...ometric-series )
9. (Original post by Charles Omer)
I believe this is correct too.
Attachment 648996
I tHought we were meant to find k+2 or am I wrong?
10. Any ideas what 73/75 would be in UMS?
11. in question 7 dont you have 2 coordinates, -a;3a/2 and -a;-3a/2? because parabola so its symmetric
12. me too
13. How many marks was question 7
14. (Original post by TrueDAN)
Any ideas what 73/75 would be in UMS?
My guess, above 90, probably 95/96
what question was the p=20 one?
Was the complex numbers second term 1/13i(3p-8) - I got p =20 though
16. Was it k(2^r-1) or k(2^r -1), i'm pretty sure it was the latter?
17. (Original post by Prodanski)
in question 7 dont you have 2 coordinates, -a;3a/2 and -a;-3a/2? because parabola so its symmetric
No because q>0
18. (Original post by Nik298)
a would be ±4.5 surely as 27/2 wouldn't lead to the correct area
You needed to realise the area could have been negative by going under the x-axis, hence area is -270 as well as 270
19. do you think its going to be ignore further working, or will i lose marks?
(Original post by Faznaz55)
No because q>0
20. I'm an idiot somehow simplified the k thing wrong so I ended up with 909/4094 instead of 910/4095

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