If I did not get number 7 and number 6 totally right, would it be A still? I am sure I got the other right.(Original post by KingsAlpaca)
My Answer for FP1 2017,
1. ST 6.45
2. (3/10, 1/10
-2/5, 1/5)
(2,1
1,-4)
3. y=x/2 xy=16 (4sqrt(2), 2sqrt(2)) and (-4sqrt(2),-2sqrt(2))
4. (2p+12)/13 + (3p-8)i/13 p=20 lambda=+-4sqrt(5)
5. (12-5p, 4p-10
6p-15, 12-5p)
p=3/2 k=15/2 a=9/2 or -27/2
6. -3-2i a=2 b=-11
7. ST (-a, -3a/2) s=15a^2/16
8. ST k=2/9
9. ST ST
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Edexcel Maths FP1 UNOFFICIAL Mark Scheme 19th May 2017 watch
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Mario Manalu
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- 101
- 19-05-2017 12:14
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- 102
- 19-05-2017 12:15
I got the same answer but youre supposed to calculate q and simplify the answers with it which i didnt.
How many marks do u think i will lose?
(I left the y coordinate and area in terms of a and q)
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- 103
- 19-05-2017 12:16
how many marks for the -27/2 one? i missed out this!
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jasminglynne
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- 104
- 19-05-2017 12:16
for the last induction question i changed f(k+1) into the same format as f(k) and then when i added 11f(k) it was divisible by 19. does this sound vaguely right to anyone?? had no idea what i was doing lol
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- 105
- 19-05-2017 12:18
(Original post by X_IDE_sidf)
How did you solve this one, tbh I just added it 12 times
so 2610 + k(2^(r-1)) = 3520
k(2^(r-1)) = 910
now as r is increasing you need to do K(2^0 + 2^1 + 2^2... 2^11) = 910
it came to 910/4095 = 2/9 -
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- 106
- 19-05-2017 12:18
(Original post by glad-he-ate-her)
Am i the only one who forgot the sum for 2 to the power of r-1 from c2 so manually wrote out all 12 termssuch mathematical elegance
Did the same thing.
Worried I may loose marks on it?( Method marks) -
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- 107
- 19-05-2017 12:18
(Original post by 20XX Fox)
Misread the equation for newton raphson to have be +4/x^2 rather than -. How many marks will I lose -
X_IDE_sidf
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- 108
- 19-05-2017 12:20
(Original post by erawein)
So you know the summation formula which was n/2(n+3)(2n+5) if i recall correctly, put 12 in and you got 2610.
so 2610 + k(2^(r-1)) = 3520
k(2^(r-1)) = 910
now as r is increasing you need to do K(2^0 + 2^1 + 2^2... 2^11) = 910
it came to 910/4095 = 2/9 -
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- 109
- 19-05-2017 12:20
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- 110
- 19-05-2017 12:21
Any ideas what 73/75 would be in UMS?
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- 111
- 19-05-2017 12:22
in question 7 dont you have 2 coordinates, -a;3a/2 and -a;-3a/2? because parabola so its symmetric
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unknown123123123
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- 112
- 19-05-2017 12:23
me too
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- 113
- 19-05-2017 12:24
How many marks was question 7
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X_IDE_sidf
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- 19-05-2017 12:24
(Original post by TrueDAN)
Any ideas what 73/75 would be in UMS? -
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- 115
- 19-05-2017 12:24
(Original post by Edmar Hadad)
what question was the p=20 one? -
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- 116
- 19-05-2017 12:25
Was it k(2^r-1) or k(2^r -1), i'm pretty sure it was the latter?
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- 117
- 19-05-2017 12:26
(Original post by Prodanski)
in question 7 dont you have 2 coordinates, -a;3a/2 and -a;-3a/2? because parabola so its symmetricLast edited by Faznaz55; 19-05-2017 at 12:30. -
Dan1999/17
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- 118
- 19-05-2017 12:27
(Original post by Nik298)
a would be ±4.5 surely as 27/2 wouldn't lead to the correct area -
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- 119
- 19-05-2017 12:29
do you think its going to be ignore further working, or will i lose marks?
(Original post by Faznaz55)
No because q>0 -
Protostar
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- 120
- 19-05-2017 12:29
I'm an idiot
somehow simplified the k thing wrong so I ended up with 909/4094 instead of 910/4095
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