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C2 logs confusion Watch

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    So i'm a little confused. Why isn't the 1/2 taken to be a power then quadratic is formed. Here they just added them it seems.. :confused:

    It's probably something obvious I don't see
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    (Original post by I'msoPi)
    So i'm a little confused. Why isn't the 1/2 taken to be a power then quadratic is formed. Here they just added them it seems.. :confused:

    It's probably something obvious I don't see
    What quadratic...?

    \log(x)+\frac{1}{2}\log(x)=\log(  x)+\log(x^{1/2})=\log(x\cdot x^{1/2})=\log(x^{3/2})=\frac{3}{2}\log(x)
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    This is equal to (1/2+1)log2(x) that is the same as (3/2)log2(x)
    Or
    log2(x^1)+log2(x^1^/^2) identical to 1*log2(x)+0.5*log2(x)

    There is no quadratic formed in this identity you are 1 step from the end from the given identity
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    (Original post by I'msoPi)
    So i'm a little confused. Why isn't the 1/2 taken to be a power then quadratic is formed. Here they just added them it seems.. :confused:

    It's probably something obvious I don't see
    You have to use the log rules
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    (Original post by RDKGames)
    What quadratic...?

    \log(x)+\frac{1}{2}\log(x)=\log(  x)+\log(x^{1/2})=\log(x\cdot x^{1/2})=\log(x^{3/2})=\frac{3}{2}\log(x)
    Gosh! As soon as I pressed send I realised it cant possibly be a quadratic. I'm so silly :laugh:
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    (Original post by I'msoPi)
    So i'm a little confused. Why isn't the 1/2 taken to be a power then quadratic is formed. Here they just added them it seems.. :confused:

    It's probably something obvious I don't see
    Aha thanks for everyone waking me up. I've had a long day :sleep:
 
 
 
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