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    Name:  jy.png
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Size:  63.0 KB Hi for this question I am unsure although I got it right.
    So the mole ratio is 1:2 , 2 moles of NaOH is used. Normally for these question the mole ratio is 1:1. So I am uncertain about which moles of compound I should be calculating. Why do I just use the moles of NaOH in this question?

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    (Original post by coconut64)
    Name:  jy.png
Views: 120
Size:  63.0 KB Hi for this question I am unsure although I got it right.
    So the mole ratio is 1:2 , 2 moles of NaOH is used. Normally for these question the mole ratio is 1:1. So I am uncertain about which moles of compound I should be calculating. Why do I just use the moles of NaOH in this question?

    Thanks
    You have to use the moles of the limiting reagent as the other does not all react, remembering that enthalpy of neutralisation is defined per mole of water formed.
 
 
 
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