I got that too! Could you tell me how did you solve it?
Since it said, both circles touch the circle, one circle touches A and another circle touches B A(1,4) B(7,8) and we know the centre for both (0,0) so one radius is (1^2 + 4 ^2) = 17^1/2 and another radius is (7^2 + 8^2) = 113^1/2
Since it said, both circles touch the circle, one circle touches A and another circle touches B A(1,4) B(7,8) and we know the centre for both (0,0) so one radius is (1^2 + 4 ^2) = 17^1/2 and another radius is (7^2 + 8^2) = 113^1/2
I solved it in the same way. But many people are saying we have to consider circle 1's diameter when calculating the radii of c2 and c3
Paper was cool, what did y'all get for area under the curve question? I got 51.75
For the last harbour question, I got h = 5.30 meters and time of 7 and 10
I can't remember what I got for area under curve but what I did was find the area of curve using integration and then find the area of the small triangle and then add them together. And I also got 5.30m. What did you do for the circle question?
What was the asymptote for the graph, I just mirrored the graph on the x axis and got an asymptote of y = -10. (Basically just changed all the y coordinates to negative)
What was the asymptote for the graph, I just mirrored the graph on the x axis and got an asymptote of y = -10. (Basically just changed all the y coordinates to negative)
What was the asymptote for the graph, I just mirrored the graph on the x axis and got an asymptote of y = -10. (Basically just changed all the y coordinates to negative)