Heat Capacity in Equilibrium Question

Watch
barnesj
Badges: 2
Rep:
?
#1
Report Thread starter 3 years ago
#1
A mass of 0.35kg of ice at −15∘C is lowered into an insulated beaker containing 0.61kg of water at 59∘C. What is the temperature after equilibrium has been reached? Give your answer in ∘C

I've been using the equation m1*c1*ΔT1 = m2*c2*ΔT2 (where m is mass, c is specific heat capacity and ΔT is temperature change) and rearranging it into
Final Temperature = m1*c1*T1 + m2*c2*T2/m1*c1 + m2*c2
but i'm not getting the right answer. I'm not sure where I'm going wrong but some help would be appreciated.
0
reply
dipsc15
Badges: 5
Rep:
?
#2
Report 2 years ago
#2
5.6 degrees C
0
reply
dipsc15
Badges: 5
Rep:
?
#3
Report 2 years ago
#3
(Original post by dipsc15)
5.6 degrees C
mcDT+ml+mcDT=mcDT
(0.35*2030*15)+(0.35*3.35x10^5)+ (0.35*4180*T)=(0.61*4180*(59-T))
Ice has to get energy to reach 0 degrees then get energy to melt then get energy to reach equilibrium temp. It gets this energy from the energy released by the 0.61kg water, as it cools down, the 'ice' water heats up, hence getting an answer of 5.6°C
1
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

Have you experienced financial difficulties as a student due to Covid-19?

Yes, I have really struggled financially (20)
13.33%
I have experienced some financial difficulties (41)
27.33%
I haven't experienced any financial difficulties and things have stayed the same (62)
41.33%
I have had better financial opportunities as a result of the pandemic (23)
15.33%
I've had another experience (let us know in the thread!) (4)
2.67%

Watched Threads

View All