A mass of 0.35kg of ice at −15∘C is lowered into an insulated beaker containing 0.61kg of water at 59∘C. What is the temperature after equilibrium has been reached? Give your answer in ∘C
I've been using the equation m1*c1*ΔT1 = m2*c2*ΔT2 (where m is mass, c is specific heat capacity and ΔT is temperature change) and rearranging it into
Final Temperature = m1*c1*T1 + m2*c2*T2/m1*c1 + m2*c2
but i'm not getting the right answer. I'm not sure where I'm going wrong but some help would be appreciated.