PbSO4 (s) + 2e- ----> Pb (s) + SO4 2- (aq) E= -0.356V
PbO2 (s) + SO4 2- (aq)+ 4H+ + 2e- ----> PbSO4 (s)+ 2H2O (l) E= +1.685 V
Cell diagram: Pb| PbSO4 || PbO2 | PbSO4
why isnt SO42-, H+ or H20 included in the cell diagram?
Well you're going to have to look at the equations and see what's getting oxidised and reduced. The H remains at 1+, S remains at 2+ and oxygen remains at 2-. Pb however changes oxidation state and so it's involved in the equation.
Well you're going to have to look at the equations and see what's getting oxidised and reduced. The H remains at 1+, S remains at 2+ and oxygen remains at 2-. Pb however changes oxidation state and so it's involved in the equation.
ok so anything that doesnt get reduced or oxidised is not included in the cell notation?