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Predict what would be observed. Explain the observations in terms of both equilibrium 1 and equilibrium 2 and any species formed.
Hi, I know that when silver nitrate is added to 2, a yellow ppt forms (AgI) as the silver ions react with the I- ions. But I don't understand why there will be any reaction in 1. There is no I- ions in 1 but apparently the postion of equilibrium will shift to the left and soild I2 forms. Why??
Thanks
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(Original post by coconut64)
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The student adds an excess of aqueous silver nitrate, AgNO3(aq), to the equilibrium mixture.
Predict what would be observed. Explain the observations in terms of both equilibrium 1 and equilibrium 2 and any species formed.
Hi, I know that when silver nitrate is added to 2, a yellow ppt forms (AgI) as the silver ions react with the I- ions. But I don't understand why there will be any reaction in 1. There is no I- ions in 1 but apparently the postion of equilibrium will shift to the left and soild I2 forms. Why??
Thanks
Predict what would be observed. Explain the observations in terms of both equilibrium 1 and equilibrium 2 and any species formed.
Hi, I know that when silver nitrate is added to 2, a yellow ppt forms (AgI) as the silver ions react with the I- ions. But I don't understand why there will be any reaction in 1. There is no I- ions in 1 but apparently the postion of equilibrium will shift to the left and soild I2 forms. Why??
Thanks
OK, forget equilibrium 1 for a moment.
Addition of silver ions to equilibrium 2 removes iodide ions and pulls the equilibrim to the LHS. This also makes more iodine in solution.
Now refer to equilibrium 1 and you will see the effect of increasing the amount of iodine drives this equilibrium to the LHS making more solid iodine.
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(Original post by charco)
Read the question. You must explain the observation in terms of both equilibrium 1 and equilibrium 2.
OK, forget equilibrium 1 for a moment.
Addition of silver ions to equilibrium 2 removes iodide ions and pulls the equilibrim to the LHS. This also makes more iodine in solution.
Now refer to equilibrium 1 and you will see the effect of increasing the amount of iodine drives this equilibrium to the LHS making more solid iodine.
Read the question. You must explain the observation in terms of both equilibrium 1 and equilibrium 2.
OK, forget equilibrium 1 for a moment.
Addition of silver ions to equilibrium 2 removes iodide ions and pulls the equilibrim to the LHS. This also makes more iodine in solution.
Now refer to equilibrium 1 and you will see the effect of increasing the amount of iodine drives this equilibrium to the LHS making more solid iodine.
Thanks
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