OCR S2 (non-mei) Wednesday 14th June

1. Unrepresentative, Random sample
2. m=48.95 theta= 25 a=16.9
3. X>=23 0.0076 reject H0
4. m= 6.18 s^2= 0.16 0.0359 do not reject & standardising
5. 0.1429 N=90
6. 0.4763 r=5 0.0375
7. 32/15 2rt2
8. np<5 0.046, 0.192, 0.95, 0.046 & p>=0.9848

Think I got 68/69

Was out of 72 buh

How many marks was the last part of the last question? Was it 2?

4 I think

Does anyone remember how many marks the N question was?

I did everything right apart from using 1.645 instead 2.807, brain must've been on autopilot

Do you know what question it was because i wrote on my calculator how many marks were worth each part of each question but not which one was which?

anyone remember all the numerical figures in question 2, want to do question again to see if I remember getting it right.

Last part of question 5 mate

1) Not representative of population- sample favours people who have are potentially more interested in school (1 mark)
b) Obtain a list of parents and assign number to each person, use random numbers and ignore any repeats (2 marks)
2) a= 16.9 (6 marks?)
3) 0.0076<0.01 reject H0, can use approximation as np>5 and n>50 (7 marks?)
4i)0.0395...>0.025 do no reject H0 (11 marks)
ii) When finding distribution of x bar (1 mark)
5i) 0.1429
5ii) N=90
6) R=5
7i) 32/15 (3 marks)
ii)show that (3 marks)
7iii) q=2rt2 (4 marks)
8i) Nq=2<5 (1 mark)
ii) Put x<60 (0.19ish) in and x=60 (0.042ish) (4 marks)
iii) p=0.95, probability= 0.442 (ish) (2 marks)
iv) 1>=p>0.9897 (4 marks)

Any different answers?

1) Not representative of population- sample favours people who have are potentially more interested in school (1 mark)
b) Obtain a list of parents and assign number to each person, use random numbers and ignore any repeats (2 marks)
2) a= 16.9 (6 marks?)
3) 0.0076<0.01 reject H0, can use approximation as np>5 and n>50 (7 marks?)
4i)0.0395...>0.025 do no reject H0 (11 marks)
ii) When finding distribution of x bar (1 mark)
5i) 0.1429
5ii) N=90
6) R=5
7i) 32/15 (3 marks)
ii)show that (3 marks)
7iii) q=2rt2 (4 marks)
8i) Nq=2<5 (1 mark)
ii) Put x<60 (0.19ish) in and x=60 (0.042ish) (4 marks)
iii) p=0.95, probability= 0.442 (ish) (2 marks)
iv) 1>=p>0.9897 (4 marks)

Any different answers?