# Edexcel physics Unit 2 IAL 2017 may/June unofficial mark scheme Watch

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#2

(Original post by

How was the exam guys? I found it quite easy.

**Luj99**)How was the exam guys? I found it quite easy.

secondly what was the mas power in internal resistance

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What I did for the last question was, I used my protractor to calculate the angle. the scale was (20 degrees in paper=40 degrees and then I converted using the value I calculated for the angle.After that I used the formula (μ1v1=μ2v2) to get the refractive index.the value I got was 1.12 I think

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(Original post by

what about the left and the right ear??

**quraisht**)what about the left and the right ear??

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#7

(Original post by

What I did for the last question was, I used my protractor to calculate the angle. the scale was (20 degrees in paper=40 degrees and then I converted using the value I calculated for the angle.After that I used the formula (μ1v1=μ2v2) to get the refractive index.the value I got was 1.12 I think

**Luj99**)What I did for the last question was, I used my protractor to calculate the angle. the scale was (20 degrees in paper=40 degrees and then I converted using the value I calculated for the angle.After that I used the formula (μ1v1=μ2v2) to get the refractive index.the value I got was 1.12 I think

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#8

(Original post by

I wasn't sure about that question , I just wrote destructive superposition occurred in right ear , what did you do for the last question

**Luj99**)I wasn't sure about that question , I just wrote destructive superposition occurred in right ear , what did you do for the last question

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(Original post by

they literally said it is not to scale

**FutureStripper**)they literally said it is not to scale

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#10

Mayn That Polarizing Filter We Had To Choose It was A Not B And Yeah Last Question Was Bad For Everyone I Think So!

Btw Was The Answer For SI Unit Ampere? and that charge was it 5.00 Coulomb? was the maximum displacement magnitude one amplitude? .

was the answer 3V for last question in MCQ's ?

i supposed 64 was the wavelength. And phase difference was somehow pie/2.it is wrong i think so....

In that intensity question i wrote about direct proportional to amplitude square and doppler effect. I hope its correct?

was the internal resistance 4.2? and emf 5.8? what was the power?

In the mean charge carriers were the electrons moving > or < ?.. i wrote > ...

I hope the grade boundaries are like 55 A something i hope so cause i will be losing atleast 25 marks maximum

Btw Was The Answer For SI Unit Ampere? and that charge was it 5.00 Coulomb? was the maximum displacement magnitude one amplitude? .

was the answer 3V for last question in MCQ's ?

i supposed 64 was the wavelength. And phase difference was somehow pie/2.it is wrong i think so....

In that intensity question i wrote about direct proportional to amplitude square and doppler effect. I hope its correct?

was the internal resistance 4.2? and emf 5.8? what was the power?

In the mean charge carriers were the electrons moving > or < ?.. i wrote > ...

I hope the grade boundaries are like 55 A something i hope so cause i will be losing atleast 25 marks maximum

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#12

**Luj99**)

I wasn't sure about that question , I just wrote destructive superposition occurred in right ear , what did you do for the last question

Its all about diffraction

- Maximum diffration occurs when the gap size is equal to wavelenght

- when frequency increases wavelenght decreases this causes most of the sound to be reflected back while only some to be heard

- than you refer it back to intensity which is equal to power/area

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#13

(Original post by

Whoa what? i talked about diffraction, wavelength, frequency and intensity. Why destructive superposition?

**umang-23**)Whoa what? i talked about diffraction, wavelength, frequency and intensity. Why destructive superposition?

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#14

(Original post by

Mayn That Polarizing Filter We Had To Choose It was A Not B And Yeah Last Question Was Bad For Everyone I Think So!

Btw Was The Answer For SI Unit Ampere? and that charge was it 5.00 Coulomb? was the maximum displacement magnitude one amplitude? .

was the answer 3V for last question in MCQ's ?

i supposed 64 was the wavelength. And phase difference was somehow pie/2.it is wrong i think so....

In that intensity question i wrote about direct proportional to amplitude square and doppler effect. I hope its correct?

was the internal resistance 4.2? and emf 5.8? what was the power?

In the mean charge carriers were the electrons moving > or < ?.. i wrote > ...

I hope the grade boundaries are like 55 A something i hope so cause i will be losing atleast 25 marks maximum

**LittlePrince**)Mayn That Polarizing Filter We Had To Choose It was A Not B And Yeah Last Question Was Bad For Everyone I Think So!

Btw Was The Answer For SI Unit Ampere? and that charge was it 5.00 Coulomb? was the maximum displacement magnitude one amplitude? .

was the answer 3V for last question in MCQ's ?

i supposed 64 was the wavelength. And phase difference was somehow pie/2.it is wrong i think so....

In that intensity question i wrote about direct proportional to amplitude square and doppler effect. I hope its correct?

was the internal resistance 4.2? and emf 5.8? what was the power?

In the mean charge carriers were the electrons moving > or < ?.. i wrote > ...

I hope the grade boundaries are like 55 A something i hope so cause i will be losing atleast 25 marks maximum

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#15

(Original post by

Does anyone know how to do the last question ?

**Luj99**)Does anyone know how to do the last question ?

Because you had been given 20 degrees at the top. Then you had 90 degrees so you subtract the total from 180 and get 70 degrees

Then from the normal it's 90 again so you do 90-70=20

Then use the refractive index of both materials

n=sin i/sin r

but again I'm not 100% sure that's just what I did

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(Original post by

SERIOUSLY DOPPLER?????????? you know that only happens when the source is moving right anyhow everything else seems to be correct

**Jacopo Innocenzi**)SERIOUSLY DOPPLER?????????? you know that only happens when the source is moving right anyhow everything else seems to be correct

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#17

By it i mean i wrote like the frequency is less and from the graph that it is decreasing. i only wrote that it diffracts and spreads! with wavelength increasing and etc.

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#18

(Original post by

I found angle of i as 20 degrees

Because you had been given 20 degrees at the top. Then you had 90 degrees so you subtract the total from 180 and get 70 degrees

Then from the normal it's 90 again so you do 90-70=20

Then use the refractive index of both materials

n=sin i/sin r

but again I'm not 100% sure that's just what I did

**Bobby.12**)I found angle of i as 20 degrees

Because you had been given 20 degrees at the top. Then you had 90 degrees so you subtract the total from 180 and get 70 degrees

Then from the normal it's 90 again so you do 90-70=20

Then use the refractive index of both materials

n=sin i/sin r

but again I'm not 100% sure that's just what I did

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#19

(Original post by

By it i mean i wrote like the frequency is less and from the graph that it is decreasing. i only wrote that it diffracts and spreads! with wavelength increasing and etc.

**LittlePrince**)By it i mean i wrote like the frequency is less and from the graph that it is decreasing. i only wrote that it diffracts and spreads! with wavelength increasing and etc.

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#20

**Bobby.12**)

I found angle of i as 20 degrees

Because you had been given 20 degrees at the top. Then you had 90 degrees so you subtract the total from 180 and get 70 degrees

Then from the normal it's 90 again so you do 90-70=20

Then use the refractive index of both materials

n=sin i/sin r

but again I'm not 100% sure that's just what I did

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