# Capacitance multiple choice questionWatch

Thread starter 1 year ago
#1

What do you do here? 🤔

Kyx britishtf2 Ihatescales
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1 year ago
#2
(Original post by LeCroissant)

What do you do here? 🤔

Kyx britishtf2 Ihatescales
First write a list of the equations that link voltage, charge, and capacitance. Then you can use them to see which answers you get

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0
1 year ago
#3
Remember that the capacitance you are looking for is the minimum also from the range given
0
1 year ago
#4
Explained well enough above - if still confused, I'm sure I/others can post a solution/more help.
0
1 year ago
#5
C = Q/V and therefore V = Q/C
If the capacitance is halved, and the charge is constant, the pd must double.
If the pd is 96, and we know the capacitance is 3x10^-12, then the charge must be 2.9x10^-10.
As (2.9x10^-10) / (96) = 2.784x10^-12, if the charge was 1.4x10^-10, then we'd be a factor of 2 out.
So I believe the answer is C.
However if I'm wrong, anyone, feel free to correct me!
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1 year ago
#6
(Original post by LeCroissant)
What do you do here?

First, calculate the charge with and . That eliminates D.

Finally, we know that . As the charge is constant, and the capacitance has halved, we know that the voltage will double.
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