#1
http://www.ocr.org.uk/Images/79737-q...nian-world.pdf

http://www.ocr.org.uk/Images/64639-m...ld-january.pdf

2cii why is the time *by 0.25
0
2 years ago
#2
It takes 1/4 of the period to go from zero to max amplitude. Because the graph of displacement vs time is not given for the vibration of cone, this (1/4 of the period) is one of the appropriate time interval that we can use to compute the average power.
You can use the whole period as suggested by the MS but you need to use the total distance travelled by the cone to compute the average power.
0
#3
(Original post by Eimmanuel)
It takes 1/4 of the period to go from zero to max amplitude. Because the graph of displacement vs time is not given for the vibration of cone, this (1/4 of the period) is one of the appropriate time interval that we can use to compute the average power.
You can use the whole period as suggested by the MS but you need to use the total distance travelled by the cone to compute the average power.
Oh wow, excellent observation. Thanks for clearing that up.
0
2 years ago
#4
(Original post by Eimmanuel)
It takes 1/4 of the period to go from zero to max amplitude. Because the graph of displacement vs time is not given for the vibration of cone, this (1/4 of the period) is one of the appropriate time interval that we can use to compute the average power.
You can use the whole period as suggested by the MS but you need to use the total distance travelled by the cone to compute the average power.
I'm sorry I am still confused, can you please help. Why is the time taken to reach the amplitude from zero 1/4 period, is this just a fact we must remember or is it given somewhere that I may have skimmed over?
0
2 years ago
#5
(Original post by BrainJuice)
I'm sorry I am still confused, can you please help. Why is the time taken to reach the amplitude from zero 1/4 period, is this just a fact we must remember or is it given somewhere that I may have skimmed over?
Look at Fig 2.1 and it would show you this fact. Yes, it is something you need to know for SHM.
0
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