Centre of Mass of a frustrum (M2)

Given that H=24 and h=12, find the distance of the centre of mass from the larger plane face of the frustrum.

H is the overall height of what would be a cone and the h is the height of the small cone on top then is cut off. does anyone have any ideas?

Reply 1

steve10

m is the mass of the small cone, h = 12
M is the mass of the frustrum
(m+M) is the mass of (what would be) the large cone, H = 24

x is the cog of the small cone = (2/3)h
C is the cog of the large cone = (2/3)H
X is the cog of the frustrum

Take moments of the composite parts (small cone and frustum) about the apex of the large cone.
Equate with moment of the large cone about the apex.

I got X = 120/7.

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