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How did everybody find it? It was unlike any of the past papers. Do you think the grade boundaries will be high or low?
Did anyone know how do answer the distance Q on the Cepheid Variable? I thought we would have to use the formula M=m+5-5 log d but the syllabus clearly states that we do not need to know how to find the distance.
Did anyone know how do answer the distance Q on the Cepheid Variable? I thought we would have to use the formula M=m+5-5 log d but the syllabus clearly states that we do not need to know how to find the distance.
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#2
I think you wsgould give up and just study somethink like math cauise math can get you a long way in life I used to study it but then my teafcher left and now I just play gamees this is wot happensd when yo pick uncommon subjects
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(Original post by abc-10)
I think you wsgould give up and just study somethink like math cauise math can get you a long way in life I used to study it but then my teafcher left and now I just play gamees this is wot happensd when yo pick uncommon subjects
I think you wsgould give up and just study somethink like math cauise math can get you a long way in life I used to study it but then my teafcher left and now I just play gamees this is wot happensd when yo pick uncommon subjects
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#4
I thought the paper was quite hard. I ended up just using the formula in the exam but think I realised how they wanted us to do it afterwards:
If apparent and absolute mag were the same then the star would be at 10pc.
But the apparent mag was 3 magnitudes less than absolute magnitude so the brightness difference would be around 16.
Therefore the star would be around 4 x further away than 10pc (due to inverse square law) and so 40pc.
I got the same answer with the formula - tell me if you think it's right. Hopefully they'll give me some marks :/
Posted from TSR Mobile
If apparent and absolute mag were the same then the star would be at 10pc.
But the apparent mag was 3 magnitudes less than absolute magnitude so the brightness difference would be around 16.
Therefore the star would be around 4 x further away than 10pc (due to inverse square law) and so 40pc.
I got the same answer with the formula - tell me if you think it's right. Hopefully they'll give me some marks :/
Posted from TSR Mobile
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(Original post by meg.s)
I thought the paper was quite hard. I ended up just using the formula in the exam but think I realised how they wanted us to do it afterwards:
If apparent and absolute mag were the same then the star would be at 10pc.
But the apparent mag was 3 magnitudes less than absolute magnitude so the brightness difference would be around 16.
Therefore the star would be around 4 x further away than 10pc (due to inverse square law) and so 40pc.
I got the same answer with the formula - tell me if you think it's right. Hopefully they'll give me some marks :/
Posted from TSR Mobile
I thought the paper was quite hard. I ended up just using the formula in the exam but think I realised how they wanted us to do it afterwards:
If apparent and absolute mag were the same then the star would be at 10pc.
But the apparent mag was 3 magnitudes less than absolute magnitude so the brightness difference would be around 16.
Therefore the star would be around 4 x further away than 10pc (due to inverse square law) and so 40pc.
I got the same answer with the formula - tell me if you think it's right. Hopefully they'll give me some marks :/
Posted from TSR Mobile
The paper wasn't hard as much as confusing. Most of the time I couldn't understand what the question was asking me to do. They better give us low grade boundaries or I swear... 😂😭😂
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#6
I hope so
You're right - it took me so long to realise one of the photos was actually of the aurora
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You're right - it took me so long to realise one of the photos was actually of the aurora
Posted from TSR Mobile
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#7
all the nerds at my school went off on one about the cepheid variable question, I just randomly tapped my calculator for half an hour and I somehow made it to 40 Pc
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#8
(Original post by S.Sage)
How did everybody find it? It was unlike any of the past papers. Do you think the grade boundaries will be high or low?
Did anyone know how do answer the distance Q on the Cepheid Variable? I thought we would have to use the formula M=m+5-5 log d but the syllabus clearly states that we do not need to know how to find the distance.
How did everybody find it? It was unlike any of the past papers. Do you think the grade boundaries will be high or low?
Did anyone know how do answer the distance Q on the Cepheid Variable? I thought we would have to use the formula M=m+5-5 log d but the syllabus clearly states that we do not need to know how to find the distance.
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#9
For that question I used trial and error by putting in values for d, and I eventually solved it I think. It was quite a weird question to throw at us, but again I suppose it is the last year of the exam.
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#12
Just seen that calculation question for the cepheid variable distance. After looking at previous years papers it was rather different and unusual compared to previous magnitude questions. Although quite challenging, I think its rather nice that they combined magnitudes with the inverse square law and the 10pc rule.
Very nice
Very nice
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