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todays methods in mathematic exam! Watch

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    guys there is a question i did today in my math exam and really want to know if i did it correctly plz help me!!!!! the question was:
    Given that p and r are two consecutive even numbers,prove algebraically that p^2+r^2 (the whole thing divide by 2) is always 1 more than (p+r)/2 (the whole thing squared.
    plz someone help!!!!!!!!!!!!
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    (Original post by maliknawaz)
    guys there is a question i did today in my math exam and really want to know if i did it correctly plz help me!!!!! the question was:
    Given that p and r are two consecutive even numbers,prove algebraically that p^2+r^2 (the whole thing divide by 2) is always 1 more than (p+r)/2 (the whole thing squared.
    plz someone help!!!!!!!!!!!!
    So if they are consecutive then r=p+2 which then means that

    \displaystyle \frac{p^2+r^2}{2}=\frac{p^2+(p+2  )^2}{2}
    and
    \displaystyle \left( \frac{p+r}{2} \right)^2 = \left( \frac{p+(p+2)}{2} \right)^2

    Expand each one out and show that indeed one is 1 more than the other.
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    (Original post by RDKGames)
    So if they are consecutive then r=p+2 which then means that

    \displaystyle \frac{p^2+r^2}{2}=\frac{p^2+(p+2  )^2}{2}
    and
    \displaystyle \left( \frac{p+r}{2} \right)^2 = \left( \frac{p+(p+2)}{2} \right)^2

    Expand each one out and show that indeed one is 1 more than the other.
    sorry i didnt understant why r=p+2
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    (Original post by maliknawaz)
    sorry i didnt understant why r=p+2
    Because if you choose some even number p, then the NEXT even number will be 2 ahead of it.
 
 
 
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