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    I thought with excess Naoh it produces [Al(OH)4]-?
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    (Original post by Super199)
    I thought with excess Naoh it produces [Al(OH)4]-?
    at first yes, probably.

    [Al(H2O)6]3+ can exchange all of its water molecules one by one with hydroxide ions
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    (Original post by charco)
    at first yes, probably.

    [Al(H2O)6]3+ can exchange all of its water molecules one by one with hydroxide ions
    So I wouldn't get the mark for just the [Al(OH)4]-?
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    (Original post by Super199)
    So I wouldn't get the mark for just the [Al(OH)4]-?
    By mark scheme combination of 4 and 5 you would get the full marks
 
 
 
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