I'd say lower than usual, those two papers combined were harder than the 2015 papers, and that was 140 for an A^. Either way, 151 and 165 will both almost definitely be an A^

Reply 48

Tomazza123

Original post by Loci Pi

What do you think between 151 and 165 will be? Do you think the boundaries will be higher or lower than usual?

I'd say lower than usual, those two papers combined were harder than the 2015 papers, and that was 140 for an A^. Either way, 151 to 165 will almost definitely be an A^

Reply 49

B0redBrioche

Original post by Npt512

do you guys still remember what q23 was?

Prove that 1/tan^2 x -1/cos^2 x(maybe sin^2 x idk) is a constant or something and you get -1 as an answer when you simplify it

Reply 50

BerylTheBird

Does anyone remember that last question? I think I messed it up

Reply 51

darude_sand

Original post by gcse0

How?
Could you show your working?
I thought it was 4.8*0.5*8 = 19.2
8-3.2 = 4.8 which was the y-coordinate

You had to split the area into to triangles, as you can't directly work out the area from (4.8*0.5*8). I don't know how you got 8, agree with you on 4.8 though. Did you work out the x coord of the point C, or whatever it was (the point in the middle)? And are you sure it was 8 for the x axis, and not 10? Because I remember C being at (4, 4.8) (I think that was it), and so as the total length was 10, you had two triangles. So then I did (6*0.5*4.8) + (4*4.8*0.5) = 24. I could be wrong I guess but I'm pretty sure that was on the right lines at least.

Original post by Npt512

i swear it was 16 square units

What was your working out?

Reply 52

Loci Pi

Original post by Tomazza123

I'd say lower than usual, those two papers combined were harder than the 2015 papers, and that was 140 for an A^. Either way, 151 to 165 will almost definitely be an A^

Yay, thanks :smile:

I think the boundary for A^ will be between 138 and 142. I found these papers really hard but I didn't find the 2015 paper too bad.

Reply 53

darude_sand

Original post by gcse0

How?
Could you show your working?
I thought it was 4.8*0.5*8 = 19.2
8-3.2 = 4.8 which was the y-coordinate

Yeah 8 might have been the base not 10 actually, still not 100% sure though

Reply 54

JohnC12321

What were the questions/working outs for these answers?:

8. 106.7
9. x=-2
10. 15.2
13. 50a^2 / 3
18. (32/5) y^2

Reply 55

darude_sand

Original post by etothepiiplusone

1a. 30
b. -1.5
2a. 13 -2
6 1
b. 11/8
c. Because number of columns of B does not equal rows of A
3a. e.g 3, 5, 91
b. Factorised ab-11b = b(a-11) so b is arbitrary square e.g 4, a=36
4. 2744
5. 4/5
6. 12.31
7. 16
8. 106.7
9. x=-2
10. 15.2
11b. -5 <= f(x) <= 7
12a. 3(5-x)(5+x)
b. 12n
13. 50a^2 / 3
14. a=4, b=10
15. y=(8x)/(w+1)
16a.3^(-2b)
b. 5^(x+2)
c. 2^(3m)
17a. (4, -25)
c. 5.79 and 1.21
18. (32/5) y^2
19a.k
b. -k
c. sqrt(1-k^2)
20a. Angle at circumference is half angle at centre
b. e.g Angle in triangle 90-x
Angle on straight line 90+x
Opposite angle in cyclic quadrilateral 90-x
Other base angle 90-x
Other angle in triangle 180-2(90-x) = 2x QED
21a. (0, 8)
b. -2x+2
c. Normal equation y=-1/2 x + 8
So intersects at (16, 0)
2*6 = 16-4
22. (-6/5, -7/5) and (2, 5)
23. -1
24. 3(2x-5)^2 - 70

Can you please put the marks in, I don't care if they are only a guestimate

Please someone make a list of marks, I want to see how I did, +rep to whoever wants to

Reply 56

username2980692

What do you think 140 would be? A*? I really wanted that A^... oh well

Reply 57

username2552331

Not sure about the others, but for 13. 50a^2 / 3 it was a 3 mark question where you had to simplify three fractions (one multiplied and one divided) that had powers of a.