2017 AQA Level 2 Further Maths Paper 2 Unofficial Mark Scheme

you can see from the diagram that OBP = 8 x 4 x 0.5 = 16

You had to split the area into to triangles, as you can't directly work out the area from (4.8*0.5*8). I don't know how you got 8, agree with you on 4.8 though. Did you work out the x coord of the point C, or whatever it was (the point in the middle)? And are you sure it was 8 for the x axis, and not 10? Because I remember C being at (4, 4.8) (I think that was it), and so as the total length was 10, you had two triangles. So then I did (6*0.5*4.8) + (4*4.8*0.5) = 24. I could be wrong I guess but I'm pretty sure that was on the right lines at least.

What were the questions for?:
8. 106.7
9. x=-2
10. 15.2
18. (32/5) y^2

1a. 30
b. -1.5
2a. 13 -2
6 1
b. 11/8
c. Because number of columns of B does not equal rows of A
3a. e.g 3, 5, 91
b. Factorised ab-11b = b(a-11) so b is arbitrary square e.g 4, a=36
4. 2744
5. 4/5
6. 12.31
7. 16
8. 106.7
9. x=-2
10. 15.2
11b. -5 <= f(x) <= 7
12a. 3(5-x)(5+x)
b. 12n
13. 50a^2 / 3
14. a=4, b=10
15. y=(8x)/(w+1)
16a.3^(-2b)
b. 5^(x+2)
c. 2^(3m)
17a. (4, -25)
c. 5.79 and 1.21
18. (32/5) y^2
19a.k
b. -k
c. sqrt(1-k^2)
20a. Angle at circumference is half angle at centre
b. e.g Angle in triangle 90-x
Angle on straight line 90+x
Opposite angle in cyclic quadrilateral 90-x
Other base angle 90-x
Other angle in triangle 180-2(90-x) = 2x QED
21a. (0, 8)
b. -2x+2
c. Normal equation y=-1/2 x + 8
So intersects at (16, 0)
2*6 = 16-4
22. (-6/5, -7/5) and (2, 5)
23. -1
24. 3(2x-5)^2 - 70

Idk, but I think the first mark is going to be substituting 20 and 9 into the nth term and the second mark is going to be the answer. So I think -30 will be in the accept column.

Do you guys think that 150-159 would be A^. I think I am going to get 152 roughly would that equate to an A^?
Do you think the grade boundaries would be lower than last year since the exams were harder, both paper 1 and paper 2?

I'm about to edit the mark scheme with a bit more detail and $LaTeX$. Hope it helps!

Q1 difference between 20th and 8th terms = 20th term - 8th term = -30?

I think the boundaries will be lower this year. The A^ boundary in 2015 was 140, and these exams were much harder than that (in my opinion). I think you've got enough marks for an A^.

Congratulations on such a great mark

Could any one explain to me the last question, i got 12(x-5/2)^2-70 but know that it is wrong because 5/2 is not an integer