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2017 AQA Level 2 Further Maths Paper 2 Unofficial Mark Scheme Watch

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  • View Poll Results: How many marks do you think you got?
    0-30
    6
    3.33%
    31-50
    11
    6.11%
    51-60
    17
    9.44%
    61-70
    16
    8.89%
    71-80
    25
    13.89%
    81-90
    29
    16.11%
    91-100
    54
    30.00%
    101-105
    22
    12.22%

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    2
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    Does anyone remember question 9 with the answer x = -2?
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    0
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    are you 100% sure about the answers to q16?
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    12
    ReputationRep:
    What question was the one about the cone and the radius?
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    0
    ReputationRep:
    What was Q22??
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    8
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    What were the questions for?:
    8. 106.7
    9. x=-2
    10. 15.2
    18. (32/5) y^2
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    (Original post by Npt512)
    you can see from the diagram that OBP = 8 x 4 x 0.5 = 16

    Attachment 665876
    I can't see the attachment.
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    8
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    was q9 and 10?
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    9
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    (Original post by darude_sand)
    You had to split the area into to triangles, as you can't directly work out the area from (4.8*0.5*8). I don't know how you got 8, agree with you on 4.8 though. Did you work out the x coord of the point C, or whatever it was (the point in the middle)? And are you sure it was 8 for the x axis, and not 10? Because I remember C being at (4, 4.8) (I think that was it), and so as the total length was 10, you had two triangles. So then I did (6*0.5*4.8) + (4*4.8*0.5) = 24. I could be wrong I guess but I'm pretty sure that was on the right lines at least.
    I got 8 since the equation was 4x+5y = 40 which when simplified gives y = 8-4/5x and therefore the height has to be 8 when x is 0.
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    (Original post by JohnC12321)
    What were the questions for?:
    8. 106.7
    9. x=-2
    10. 15.2
    18. (32/5) y^2
    Q18 was the one where you had to give the area of a rectangle in terms of y

    I think the sides were x and 2x
    And the diagonal was 4y
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    (Original post by etothepiiplusone)
    1a. 30
    b. -1.5
    2a. 13 -2
    6 1
    b. 11/8
    c. Because number of columns of B does not equal rows of A
    3a. e.g 3, 5, 91
    b. Factorised ab-11b = b(a-11) so b is arbitrary square e.g 4, a=36
    4. 2744
    5. 4/5
    6. 12.31
    7. 16
    8. 106.7
    9. x=-2
    10. 15.2
    11b. -5 <= f(x) <= 7
    12a. 3(5-x)(5+x)
    b. 12n
    13. 50a^2 / 3
    14. a=4, b=10
    15. y=(8x)/(w+1)
    16a.3^(-2b)
    b. 5^(x+2)
    c. 2^(3m)
    17a. (4, -25)
    c. 5.79 and 1.21
    18. (32/5) y^2
    19a.k
    b. -k
    c. sqrt(1-k^2)
    20a. Angle at circumference is half angle at centre
    b. e.g Angle in triangle 90-x
    Angle on straight line 90+x
    Opposite angle in cyclic quadrilateral 90-x
    Other base angle 90-x
    Other angle in triangle 180-2(90-x) = 2x QED
    21a. (0, 8)
    b. -2x+2
    c. Normal equation y=-1/2 x + 8
    So intersects at (16, 0)
    2*6 = 16-4
    22. (-6/5, -7/5) and (2, 5)
    23. -1
    24. 3(2x-5)^2 - 70
    im pretty sure q8 was 106.1 (since angle = 106.06...)
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    9
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    Do you guys think that 150-159 would be A^. I think I am going to get 152 roughly would that equate to an A^?
    Do you think the grade boundaries would be lower than last year since the exams were harder, both paper 1 and paper 2?
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    (Original post by LUSer21)
    Idk, but I think the first mark is going to be substituting 20 and 9 into the nth term and the second mark is going to be the answer. So I think -30 will be in the accept column.
    but it was asking for the difference from 20th term to 8th term not 8th to 20th
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    (Original post by gcse0)
    Do you guys think that 150-159 would be A^. I think I am going to get 152 roughly would that equate to an A^?
    Do you think the grade boundaries would be lower than last year since the exams were harder, both paper 1 and paper 2?
    I think the boundaries will be lower this year. The A^ boundary in 2015 was 140, and these exams were much harder than that (in my opinion). I think you've got enough marks for an A^.

    Congratulations on such a great mark
    • Thread Starter
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    11
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    I'm about to edit the mark scheme with a bit more detail and  LaTeX . Hope it helps!
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    (Original post by etothepiiplusone)
    I'm about to edit the mark scheme with a bit more detail and  LaTeX . Hope it helps!
    Please add the marks sir I'll give you rep
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    0
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    For q14 you out 10 but that isn't a square number
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    0
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    Could any one explain to me the last question, i got 12(x-5/2)^2-70 but know that it is wrong because 5/2 is not an integer
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    (Original post by LUSer21)
    Q1 difference between 20th and 8th terms = 20th term - 8th term = -30?
    Yeah it was -30
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    (Original post by Loci Pi)
    I think the boundaries will be lower this year. The A^ boundary in 2015 was 140, and these exams were much harder than that (in my opinion). I think you've got enough marks for an A^.

    Congratulations on such a great mark
    What do you think the grade boundaries will be then roughly? Because those papers both felt much harder than past papers... 137 for the A^?
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    (Original post by HollyCo)
    Could any one explain to me the last question, i got 12(x-5/2)^2-70 but know that it is wrong because 5/2 is not an integer
    i swear that the question was 12x^2-60x+5 but the mark scheme simplifies to 12x^2-30x+5. Or did i completely miss read the question. opps. Does any one know?
 
 
 
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