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2017 AQA Level 2 Further Maths Paper 2 Unofficial Mark Scheme Watch

  • View Poll Results: How many marks do you think you got?
    0-30
    6
    3.33%
    31-50
    11
    6.11%
    51-60
    17
    9.44%
    61-70
    16
    8.89%
    71-80
    25
    13.89%
    81-90
    29
    16.11%
    91-100
    54
    30.00%
    101-105
    22
    12.22%

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    (Original post by Npt512)
    im pretty sure q8 was 106.1 (since angle = 106.06...)
    I knew something seemed wrong about that question. I got 106.1 too, glad I'm not the only one.


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    (Original post by Tomazza123)
    What do you think the grade boundaries will be then roughly? Because those papers both felt much harder than past papers... 137 for the A^?
    I think it will be around 137-141. Most of the time with the past papers, I knew what to do immediately. In today's paper though, I really had to think about what to do, especially for the last question and the trig one where you had to find k. I thought Thursday's paper was alright though. I guess that was AQA's way of tricking people into thinking today's paper was going to be good.
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    (Original post by maninblack00)
    I knew something seemed wrong about that question. I got 106.1 too, glad I'm not the only one.


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    I wrote all the answers on the back of my hand, and it's reasonable to assume I cannot read my back-of-hand-handrwriting and mistook a 1 for a 7. Since both of you agreed on that, I'll change it
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    (Original post by darude_sand)
    Please add the marks sir I'll give you rep
    In the process. I cannot remember many so please comment everyone if you do remember.

    'Sir'. Bloody hell
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    (Original post by DokBMillionaire)
    For q14 you out 10 but that isn't a square number
    Sorry, I have forgotten most of the questions. Could you describe q.14 please
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    i got around 150, maybe plus minus 5 marks. do you guys think thats an A^ cos most people thought the 2016 maths gcse edexcel paper was hard but in the end the grade boundaries were so high!
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    (Original post by etothepiiplusone)
    1a. 30 (and -30 is probably allowed) Marks=3?
    b. -1.5 Marks=?

    2a. \begin{pmatrix} -13 & 2 \\ 6 & 1 \end{pmatrix} Marks=?
    b.  \frac{11}{8} Marks=?
    c. Because the number of columns of B does not equal the number of rows of A Marks=1

    3a. Since 1365 = 3*5*7*13 , choose any two factors, multiply those together, and write the other two factors: e.g 3, 5, 91 Marks=?
    b. Factorised, ab-11b = b(a-11) so b is an arbitrary square e.g 4, and a=36 Marks=?

    4.  2744 Marks=?

    5. \frac{4}{5} Marks=?

    6. 12.31 Marks=?

    7. 16 Marks=?

    8. 106.1 Marks=?

    9. x=-2 Marks=?

    10. 15.2 Marks=?

    11a. Draw the thing. Marks=?
    11b.  -5 <= f(x) <= 7 Marks=?

    12a. 3(5-x)(5+x) Marks=?
    b. 12n Marks=?

    13. \frac{50a^2}{3} Marks=5?

    14. a=4, b=10 Marks=?

    15. y=\frac{8x}{w+1} Marks=3?

    16a. 3^{-2b} Marks=1
    b. 5^{x+2} Marks=1
    c. 2^{3m} Marks=1

    17a. (4, -25) Marks=?
    c. The roots are x=5.79 and x=1.21 Marks=?
    18. \frac{32y^2}{5} Marks=?

    19a. k. Marks=1 Think of 19a. and 19b. as transformations: https://www.desmos.com/calculator/4kphkki8vl
    b. -k Marks=1
    c.  \sqrt(1-k^2). This is rearranging of  \sin^2 x + \cos^2 x = 1 with  \sin^2 x = k^2 Marks=2

    20a. Angle at circumference is half angle at centre Marks=1
    b. e.g Angle in triangle 90-x
    Angle on straight line 90+x
    Opposite angle in cyclic quadrilateral 90-x
    Other base angle 90-x
    Other angle in triangle 180-2(90-x) = 2x, QED Marks=5?
    There are obviously many other ways to do this. I think we all know if we got or did not get marks on this question

    21a. (0, 8) Marks=?
    b. -2x+2 Marks=?
    c. Normal equation y= \frac{-1}{2}x + 8
    So intersects x-axis at (16, 0)
    The rest is easy (show one length is twice the other) Marks=?

    22.  (-6/5, -7/5) and (2, 5) were the pairs of solutions Marks=?

    23. -1 is the constant, because

     \frac{1}{\tan^2 x} - \frac{1}{\sin^2 x}

     = \frac{1}{(\frac{\sin x}{\cos x})^2} - \frac{1}{\sin^2 x}

     = \frac{1}{\frac{\sin^2 x}{\cos^2 x}} - \frac{1}{\sin^2 x}

     = \frac{\cos^2 x}{\sin^2 x} - \frac{1}{\sin^2 x}

     = \frac{\cos^2 x - 1}{\sin^2 x}

     = \frac{- (-\cos^2 x + 1)}{\sin^2 x}

     = \frac{- \sin^2 x}{\sin^2 x}

     = -1 Marks=4?

    24. 3(2x-5)^2 - 70 Marks=4?
    dude, i swear 18 is 16y^2/5, because the area x*2x/2, and x=4y/sqrt5, so x*2x/2 = (4y/sqrt5)^2
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    (Original post by jamal.academy)
    dude, i swear 18 is 16y^2/5, because the area x*2x/2, and x=4y/sqrt5, so x*2x/2 = (4y/sqrt5)^2
    Isn't the area of the rectangle x*2x=2x^2? Why divide by two?
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    (Original post by etothepiiplusone)
    Isn't the area of the rectangle x*2x=2x^2? Why divide by two?
    lol, it said find the area of the rectangle in terms of y
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    Surely
    (2^m)^3
    = 8^3m not 2^3m?
    Correct me if I'm wrong!
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    I've just realised for the area of the rectangle question I found the area of the triangle I read the question wrong.
    I found x in terms of y though. Will I get any method marks for this?
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    (Original post by Stevenscheese)
    Surely
    (2^m)^3
    = 8^3m not 2^3m?
    Correct me if I'm wrong!
    Come on Steven, these are basic exponent laws!
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    (Original post by Loci Pi)
    I've just realised for the area of the rectangle question I found the area of the triangle I read the question wrong.
    I found x in terms of y though. Will I get any method marks for this?
    lol, i made the same exact mistake, how much marks would you lose?
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    (Original post by jamal.academy)
    lol, it said find the area of the rectangle in terms of y
    Can't really remember the question. If you could further detail it it would be great
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    (Original post by jamal.academy)
    lol, it said find the area of the rectangle in terms of y
    sorry, i made a silly mistake, how much marks would i lose
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    (Original post by etothepiiplusone)
    Can't really remember the question. If you could further detail it it would be great
    nono, you are right, but can u tell me how much marks i will lose for that?
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    (Original post by jamal.academy)
    nono, you are right, but can u tell me how much marks i will lose for that?
    Tbh I have no idea. Anywhere between 1 and them all
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    (Original post by etothepiiplusone)
    Tbh I have no idea. Anywhere between 1 and them all
    between them all, omg you must be joking, am sure 2 marks
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    (Original post by Npt512)
    i swear it was 16 square units
    I got 16 aswell; 4 across and 8 down
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    (Original post by jamal.academy)
    between them all, omg you must be joking, am sure 2 marks
    'I have no idea'
 
 
 
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