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    Hi can someone please help with this question? I got 1m/s and also -0.91!


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    Snooker Ball A has a mass of 0.06kg

    Snooker ball B has a mass of 0.055kg

    Snooker ball A is moving with a velocity of 4m/s and hits snooker ball B which is stationary. Snooker ball B moves to the right with a velocity of 3m/s. What is the velocity of ball A after the collision and in what way does it move?

    (Btw this was an exam question, would just like to know the answer, don't ever need to do this again!!)
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    Momentum before = Momentum A Before + Momentum B before
    = 0.06 * 4 + 0.055 * 0
    = 0.24 kgms^-1
    Momentum after = Momentum before
    Momentum after = 0.24kgms^-1
    Momentum A After + Momentum B after = 0.24kgms^-1
    0.06 * x + 0.055 * 3 = 0.24
    x = 1.25
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    (Original post by Dench,x,Kid)
    Momentum before = Momentum A Before + Momentum B before
    = 0.06 * 4 + 0.055 * 0
    = 0.24 kgms^-1
    Momentum after = Momentum before
    Momentum after = 0.24kgms^-1
    Momentum A After + Momentum B after = 0.24kgms^-1
    0.06 * x + 0.055 * 3 = 0.24
    x = 1.25
    Thanks, I combined the 2 masses for momentum after, hopefully I'll get some marks!
 
 
 
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