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2017 Maths Edexcel C3 Unofficial Mark Scheme
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Poll: How many marks do you think you got?
0-30
(106)
4.25%
31-35
(50)
2%
36-40
(77)
3.09%
41-45
(106)
4.25%
46-50
(154)
6.17%
51-55
(318)
12.75%
56-60
(354)
14.19%
61-65
(467)
18.72%
66-70
(477)
19.12%
71-75
(386)
15.47%
gnehcnosna
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#1
1. 2/(x-3)
2a. x=3+ln2
b. y=(4e^2-5)/(e^2+2)
3a. g(x)>=3
b. g^-1(x)=(x-3)^2-2, x>=3
c. x=(7+sqrt21)/2
d. a=(7+sqrt21)/2
4a. R=sqrt29 alpha=0.3805(awrt 0.381)
b. 5cos2x-2sin2x=3
c. x=0.30 or 2.46
5a. 2x+5y=11
c. x2=1.9950 x3=1.9929
6ai. V-shaped x-int=a/2 y-int=a
ii. V-shaped y-int=a+b
b. c=4a
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1 EDIT : Answer is actually x>=1/sqrt(11) or x <= -1/sqrt{11} (see here for confirmation - scroll down for solutions)
ii.dydx= 1/[2sqrt(e^2x+1)] EDIT : This should be 1/[2sqrt(e^(2x)-1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7, 180
Please reply with any corrections
2a. x=3+ln2
b. y=(4e^2-5)/(e^2+2)
3a. g(x)>=3
b. g^-1(x)=(x-3)^2-2, x>=3
c. x=(7+sqrt21)/2
d. a=(7+sqrt21)/2
4a. R=sqrt29 alpha=0.3805(awrt 0.381)
b. 5cos2x-2sin2x=3
c. x=0.30 or 2.46
5a. 2x+5y=11
c. x2=1.9950 x3=1.9929
6ai. V-shaped x-int=a/2 y-int=a
ii. V-shaped y-int=a+b
b. c=4a
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1 EDIT : Answer is actually x>=1/sqrt(11) or x <= -1/sqrt{11} (see here for confirmation - scroll down for solutions)
ii.dydx= 1/[2sqrt(e^2x+1)] EDIT : This should be 1/[2sqrt(e^(2x)-1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7, 180
Please reply with any corrections
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Khanman123
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KloppOClock
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thelegend99
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#4
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#4
(Original post by KloppOClock)
for question 8 i think, i got something like T=3. something and P =102
for question 8 i think, i got something like T=3. something and P =102
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suwakeesh
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Khanman123
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gnehcnosna
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#7
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
Posted from TSR Mobile
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
Posted from TSR Mobile
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Kowalifwer
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#8
TanmayM98
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#9
thelegend99
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#10
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#10
(Original post by gnehcnosna)
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
Posted from TSR Mobile
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
Posted from TSR Mobile
180 for 9B as well (btw just a suggestion, would it be better if you updated the post at the beginning so people can see? cheers)
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NotNotBatman
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#11
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#11
(Original post by gnehcnosna)
1. 2/(x-3)
2a. x=3+(ln8)/3
b. y=(4e^2-5)/(e^2+2)
3a. g(x)>=3
b. g^-1(x)=(x-3)^2-2, x>=3
c. x=(7+sqrt21)/2
d. a=(7+sqrt21)/2
4a. R=sqrt29 alpha=0.3805
b. c=3
c. x=0.30 or 2.46
5a. 2x+5y=11
c. x2=1.9950 x3=1.9929
6a. V-shaped x-int=a/2 y-int=a
b. V-shaped y-int=a+b
b. c=4a
Posted from TSR Mobile
1. 2/(x-3)
2a. x=3+(ln8)/3
b. y=(4e^2-5)/(e^2+2)
3a. g(x)>=3
b. g^-1(x)=(x-3)^2-2, x>=3
c. x=(7+sqrt21)/2
d. a=(7+sqrt21)/2
4a. R=sqrt29 alpha=0.3805
b. c=3
c. x=0.30 or 2.46
5a. 2x+5y=11
c. x2=1.9950 x3=1.9929
6a. V-shaped x-int=a/2 y-int=a
b. V-shaped y-int=a+b
b. c=4a
Posted from TSR Mobile
And 4b required 2dp.
Other than that it's all good.
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Competence
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#12
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#12
Also t=3.53 pmax=102(Before u reply it said integer in q) also k=40 and last q sin=-1/2 and 0 cant remember other value
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studentsixth
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#13
Notnek
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#14
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#14
(Original post by gnehcnosna)
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
Posted from TSR Mobile
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
Posted from TSR Mobile
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suwakeesh
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#15
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#15
(Original post by gnehcnosna)
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
from TSR Mobile
7ia. dydx= 2(11x^2-1)(x^2-1)^4
b x>=1 or x<=1
ii.dydx= 1/[2sqrt(e^2x+1)]
8a.65
b. [10^-0.1t(24e^-0.9t-1)]/(1+3e^-0.9t)^2
ci. T=3.53 ii. 102
d. 40
9b. 0, 16.3, 163.7
I might be wrong lmao
from TSR Mobile
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Cheryl_Yuen
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#16
Bobrocket
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#17
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#17
What did everyone get for the question that was:
"Given x = ln(sec(2y)), work out dy/dx as a function of x"
I got 1/(2(e^x)sin(arccos(1/(e^x))))
Since dx/dy is 2tan(2y), we know that dy/dx = 1/(dx/dy) = 1/2 * cot(2y). We also can rearrange x to get y=
x = ln(sec(2y))
e^x = sec(2y)
1/(e^x) = cos(2y)
y = arccos(1/(e^x)) / 2
Which we then sub in as
1/2 * cot(arccos(1/(e^x)))
Which gets us to
1/2 * (cos(arccos(1/(e^x))) / sin(arccos(1/(e^x)))
Which is then
1/(2(e^x)sin(arccos(1/(e^x))))
Not sure if I've oversimplified (or undersimplified), but that's what I got.
"Given x = ln(sec(2y)), work out dy/dx as a function of x"
I got 1/(2(e^x)sin(arccos(1/(e^x))))
Since dx/dy is 2tan(2y), we know that dy/dx = 1/(dx/dy) = 1/2 * cot(2y). We also can rearrange x to get y=
x = ln(sec(2y))
e^x = sec(2y)
1/(e^x) = cos(2y)
y = arccos(1/(e^x)) / 2
Which we then sub in as
1/2 * cot(arccos(1/(e^x)))
Which gets us to
1/2 * (cos(arccos(1/(e^x))) / sin(arccos(1/(e^x)))
Which is then
1/(2(e^x)sin(arccos(1/(e^x))))
Not sure if I've oversimplified (or undersimplified), but that's what I got.
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suwakeesh
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#18
> Louis
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#19
frostyy
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#20
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#20
(Original post by Kowalifwer)
C=4a/7 isnt it?
C=4a/7 isnt it?
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