You are Here: Home >< Physics

# does resistance in a "ideal wire" not change due to temperature? watch

1. https://oxfordpat.wordpress.com/oxfo...6-question-13/ surely resistance increases with temperature?
2. (Original post by alvan15)
https://oxfordpat.wordpress.com/oxfo...6-question-13/ surely resistance increases with temperature?
Yes, you are correct. But be careful with the terminology.

The word 'ideal' is another way of saying a resistance follows Ohms law without needing to invoke thermal considerations or any other parameter which would cause a deviation form Ohms law such as inductance, capacitance etc.

EDIT: For an ideal conductor, there is no resistance and hence no energy losses.
3. (Original post by uberteknik)
Yes, you are correct. But be careful with the terminology.

The word 'ideal' is another way of saying the conductor follows Ohms law without needing to invoke thermal considerations or any other parameter which would cause a deviation form Ohms law such as inductance, capacitance etc.
thank you , that explains it perfectly
4. (Original post by alvan15)
https://oxfordpat.wordpress.com/oxfo...6-question-13/ surely resistance increases with temperature?
Ideal wires have zero resistance. That's why they're ideal, lol.
5. (Original post by Physics Enemy)
Ideal wires have zero resistance. That's why they're ideal, lol.
thanks :P
6. (Original post by uberteknik)
Yes, you are correct. But be careful with the terminology.

The word 'ideal' is another way of saying the conductor follows Ohms law without needing to invoke thermal considerations or any other parameter which would cause a deviation form Ohms law such as inductance, capacitance etc.
It has virtually no resistance to begin with, it's not like there's a significant resistance that's maintained despite the temperature increase.
7. (Original post by alvan15)
thank you , that explains it perfectly
Following on from Physics Enemy, yes, that does imply that an 'ideal resistance' follows Ohms law perfectly and an 'ideal conductor' is perfect with no resistance and hence no energy losses. For calculation purposes it can therefore be ignored.
8. They're testing whether you can suss out what makes a wire, or any component, ideal. You have to consider its purpose. We want a wire to conduct optimally.

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: July 17, 2017
Today on TSR

### Edexcel C2 Core Unofficial Markscheme!

Find out how you've done here

### Everything you need to know for GCSE maths

Poll

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE