Qer
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Can anyone tell me why use radian in part for and h

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Qer
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I am uploadin question
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I need help in this question ( will upload question)
Why we have to use radian in f and h
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RDKGames
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(Original post by Qer)
I need help in this question ( will upload question)
Why we have to use radian in f and h
Just upload the pic of it to http://imgur.com/ then right-click it, copy image address, and paste it here.
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Qer
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(Original post by RDKGames)
Just upload the pic of it to http://imgur.com/ then right-click it, copy image address, and paste it here.
i manage to upload

thanks
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RDKGames
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i manage to upload

thanks
We use radians because that's the natural measurement of an angle. Furthermore, calculus only works in radians and some numerical approximations make use of calculus therefore there needs to be consistency here.
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(Original post by RDKGames)
We use radians because that's the natural measurement of an angle. Furthermore, calculus only works in radians and some numerical approximations make use of calculus therefore there needs to be consistency here.
thanks but it doesnt make sense to me
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RDKGames
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thanks but it doesnt make sense to me
Probably because you were taught degrees before radians so you're more comfortable using degrees.

Word of advice: get used to radians at this level, they are really not that hard to understand and are explained just fine at C2.
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(Original post by RDKGames)
Probably because you were taught degrees before radians so you're more comfortable using degrees.

Word of advice: get used to radians at this level, they are really not that hard to understand and are explained just fine at C2.
ok
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Dysf(x)al
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(Original post by Qer)
Can anyone tell me why use radian in part for and h

Thanks
In general, you should be using radians for C3 and C4 unless otherwise stated. You can use degrees for Mechanics though.

When differentiating or integrating trigonometric functions, you must use radians. The derivative of sin(x) is only cos(x) if you're in radians. If you try it in degrees, you'll be out by a factor of 180/pi.
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