bsq_294
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Guys help me in this pls
A roller coaster train has a mass of 1500'kg, it descends from point p which is 30m above the ground to point Q which is 10 m above the ground
a) calculate the loss in gravitational potential energy of the train when it moves from point p to Q
B) if 20% of the gravitational potential energy lost is dissipated calculate the speed of the train at point Q and the kinetic energy of the train at pony Q
Plsssss solve this I can't seem to solve it
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K-Man_PhysCheM
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Do you know how to calculate gravitational potential energy?
GPE = mhg, where m is mass, h is height and g is acceleration due to gravity, which is taken as 10m/s^2 at GCSE level.

So the loss in GPE will be equal to GPE at the top minus GPE at the bottom.

Then for part b), the loss in GPE = gain in KE + heat dissipated, because of conservation of energy.

Kinetic energy is given by E_K = \frac{1}{2}mv^2, where m is mass and v is speed.

Have a go and let us know how you get on
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