Original post by Sizzo1128
y=x-4
2x^2-xy=8
The question says that I need to solve this by eliminating y but how?
2x^2-xy=8
The question says that I need to solve this by eliminating y but how?
Sub into the second equation to give .
Original post by Sizzo1128
y=x-4
2x^2-xy=8
The question says that I need to solve this by eliminating y but how?
2x^2-xy=8
The question says that I need to solve this by eliminating y but how?
Multiply the first eq through by then add the two.
Or just sub your first eq into the second one for
Original post by Sizzo1128
y=x-4
2x^2-xy=8
The question says that I need to solve this by eliminating y but how?
2x^2-xy=8
The question says that I need to solve this by eliminating y but how?
I think u have to substitute y into the other line
Are you sure it's the elimination method? I'd substitute y=x-4 into the other equation:
2x^2-x(x-4)=8
Expand and solve to find value(s) of x, then using the x value(s) find y.
2x^2-x(x-4)=8
Expand and solve to find value(s) of x, then using the x value(s) find y.
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