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    I am tryig to calculate the perpendicular distance for the 2N force in question 8.

    I was wondering why PX is equal to 6sin40, when it appears from my diagram that it can also be equal to 5sin58.

    Is there something that i am missing that means that 5sin58 is not a valid answer.




    Hope that made nay sense. Thanks
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    the book is wrong... 6sin 40° is not equal to 5sin 58°
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    The dotted line triangle does not appear to have a right angle.
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    Sorry i must have worded my initial question poorly.
    I can see two triangles both of which have a common side which seems to be the perpendicular distance from P to the 2N force.

    So i was wondering if i havent missed anything obvious why one answer is valid and the other is not.

    Ill include a drawing which hopefully clarifies my point.

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    Never mind the traingle is an impossible one. That is where the confusion is coming from.

    Thanks for ur time
 
 
 
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