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# M2 moments. Perpendicular distance confusion watch

1. I am tryig to calculate the perpendicular distance for the 2N force in question 8.

I was wondering why PX is equal to 6sin40, when it appears from my diagram that it can also be equal to 5sin58.

Is there something that i am missing that means that 5sin58 is not a valid answer.

Hope that made nay sense. Thanks
2. the book is wrong... 6sin 40° is not equal to 5sin 58°
3. The dotted line triangle does not appear to have a right angle.
4. Sorry i must have worded my initial question poorly.
I can see two triangles both of which have a common side which seems to be the perpendicular distance from P to the 2N force.

So i was wondering if i havent missed anything obvious why one answer is valid and the other is not.

Ill include a drawing which hopefully clarifies my point.

5. Never mind the traingle is an impossible one. That is where the confusion is coming from.

Thanks for ur time

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Updated: August 13, 2017
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