The Student Room Group

Fourier series question

For the last part of the question, do I just choose a value of x such that sinx=1, and this value has to be within the continuous region of the graph?

https://i.gyazo.com/bb4bceeb2a61e029d2db934ba54ecd45.png


Here is my graph;
https://i.gyazo.com/18660a9dba5784851db914e54977e68f.png


thanks
Original post by T-GiuR
...


No discontinuity as f(x) is defined for any x. If you mean x = 0, π etc why bring it up if sin(x) = 0?

Set x = π/2 so f(π/2) = k (by defn), sub into fourier expansion, cancel k's, re-arrange for π.
(edited 6 years ago)

Quick Reply

Latest