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#1
I am not sure how to find angle x. Would you draw a centre point to create triangle OBC, where O is the centre. The line OB is the radius of the triangle. The angle at C would equal to 20 degrees. The angle at B would be equal to 90 degrees, because of circle theorem 5.
O = 70 degrees
Then according to circle theorem 1 'The angle at the centre is twice the angle at the circumference' so angle x would be half of O= 35 degrees.
I am unsure if this is right or not, I do not have much experience with circle theorems so any clarity or advice would be much appreciated.
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#2
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4 years ago
#3
(Original post by Harveybishop)
I am not sure how to find angle x. Would you draw a centre point to create triangle OBC, where O is the centre. The line OB is the radius of the triangle. The angle at C would equal to 20 degrees. The angle at B would be equal to 90 degrees, because of circle theorem 5.
O = 70 degrees
Then according to circle theorem 1 'The angle at the centre is twice the angle at the circumference' so angle x would be half of O= 35 degrees.
I am unsure if this is right or not, I do not have much experience with circle theorems so any clarity or advice would be much appreciated.
Your method is not quite correct. Your angle BOC = 70 degrees. x is not half of this angle. It is half of angle BOD.

A method that you might find easier is to draw BD and think about the isosceles triangle BCD and then use the alternate segment theorem.
1
4 years ago
#4
Try putting a centre and linking it to B/D and use the theorem that those lines are perpendicular. Then use that kite to find the angle of O and thus x.
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4 years ago
#5
does this help?
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#6
(Original post by astro-hannah)
does this help?
astro-hannah Yes it does, thank you very much 😊
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4 years ago
#7
(Original post by Harveybishop)
astro-hannah Yes it does, thank you very much 😊
Yay! No probs 0
4 years ago
#8
I'm sure this exact question/image was posted a few weeks ago...
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