# Specific latent heat of vaporisation of water...

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#1
Ok I get what it means, latent means hidden therefore latent heat means ‘hidden heat’, temperature does not change however heat is being supplied, vaporisation is when liquid is converting to a gas. In all specific latent heat of vaporisation means heat being added to liquid without the temperature changing, but i've been trying to workk out this homework task question for ages!!!

While a kettle boils, 0.018 kg of water changes to steam.
Calculate the amount of energy required for this change.
Specific latent heat of vaporisation of water = 2.3 × 106 (J / kg).

Can anyone help?!?!
0
3 years ago
#2
(Original post by Stano005)
Ok I get what it means, latent means hidden therefore latent heat means ‘hidden heat’, temperature does not change however heat is being supplied, vaporisation is when liquid is converting to a gas. In all specific latent heat of vaporisation means heat being added to liquid without the temperature changing, but i've been trying to workk out this homework task question for ages!!!

While a kettle boils, 0.018 kg of water changes to steam.
Calculate the amount of energy required for this change.
Specific latent heat of vaporisation of water = 2.3 × 106 (J / kg).

Can anyone help?!?!
You can just use the formula mLv
where m is the mass of the water that changes to steam and
Lv is the specific latent heat of vaporisation of water.
0
3 years ago
#3
(Original post by Stano005)
Ok I get what it means, latent means hidden therefore latent heat means ‘hidden heat’, temperature does not change however heat is being supplied, vaporisation is when liquid is converting to a gas. In all specific latent heat of vaporisation means heat being added to liquid without the temperature changing, but i've been trying to workk out this homework task question for ages!!!

While a kettle boils, 0.018 kg of water changes to steam.
Calculate the amount of energy required for this change.
Specific latent heat of vaporisation of water = 2.3 × 106 (J / kg).

Can anyone help?!?!
Latent heat of vapourisation of water, means heat required to change1 kg of water at 100 degrees Celsius of water to 100 degrees of steam
So multiply the two given quantities
=0.018 (kg) x 2.3 x 10^6(J/Kg)
=41400 J
0
3 years ago
#4
Sorry for the syntax error in the last message. It should read " Latent Heat of Vapourisation of water is equal to the heat energy needed to convert 1Kg of water at 100 degrees Celsius to 1 Kg of steam at 100 degrees Celsius"
0
1 year ago
#5
i'm trying to work it out too
0
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