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I know what it means but I dont get this question!!! Ive been trying to work it out for ages!!!
While a kettle boils, 0.018 kg of water changes to steam.
Calculate the amount of energy required for this change.
Specific latent heat of vaporisation of water = 2.3 × 106 (J / kg).
Thanks!!!
-Ollie
While a kettle boils, 0.018 kg of water changes to steam.
Calculate the amount of energy required for this change.
Specific latent heat of vaporisation of water = 2.3 × 106 (J / kg).
Thanks!!!
-Ollie
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You need to use the equation for latent heat, which can be written as
energy (J) = mass (kg) × specific latent heat (J/kg)
So this question involves multiplying the mass of water (0.018kg) by the specific latent heat of vaporisation (2.3x10^6 J / kg) to give the answer.
energy (J) = mass (kg) × specific latent heat (J/kg)
So this question involves multiplying the mass of water (0.018kg) by the specific latent heat of vaporisation (2.3x10^6 J / kg) to give the answer.
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