ranataw
Badges: 9
Rep:
?
#1
Report Thread starter 4 years ago
#1
⦁ The following half reactions occur when potassium iodate(V), KIO3, in hydrochloric acid solution oxidises iodine to ICl 2–.
IO3– + 2Cl – + 6H+ + 4e– → ICl 2– + 3H2O
I2 + 4Cl – → 2ICl 2– + 2e–
What is the ratio of IO3– to I2 in the balanced chemical equation for the overall reaction?
A 1 : 1 B 1 : 2 C 1 : 4 D 2 : 1
plaese can someone explain the method
0
reply
Aleksander Krol
Badges: 12
Rep:
?
#2
Report 1 month ago
#2
the anwer is B. because these are half equations and in order to add them, we need to make the number of electrons on both side equal so we can cancel them out so we do this by multiplying the second equation of the question which is this one below I2 4Cl – → 2ICl 2– 2e–) by 2 to make it 4e-so we get 2I2 8Cl - → 4ICl 2– 4e–And you can see the ratio now, it's 1:2.
0
reply
Aleksander Krol
Badges: 12
Rep:
?
#3
Report 1 month ago
#3
i know this is quite an old post, but just incase if other students visits this, i hope it helps them
1
reply
hyogljl
Badges: 1
Rep:
?
#4
Report 3 weeks ago
#4
good boy
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

What support do you need with your UCAS application?

I need help researching unis (20)
14.93%
I need help researching courses (8)
5.97%
I need help with filling out the application form (7)
5.22%
I need help with my personal statement (51)
38.06%
I need help with understanding how to make my application stand out (35)
26.12%
I need help with something else (let us know in the thread!) (3)
2.24%
I'm feeling confident about my application and don't need any help at the moment (10)
7.46%

Watched Threads

View All